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nlexa [21]
2 years ago
12

Algibric equations that equal 13

Mathematics
1 answer:
inysia [295]2 years ago
3 0
(1-2+3•(45/5)/2 that equals 13
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The average is 2. To find the average you add all the numbers then divide the sum by the total amount of numbers.
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Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1, and the given zeros.
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You need to rent a video camera for your school project. Murphy's Camera charges a $30 rental fee plus $35 per day. Allied Renta
andreev551 [17]

A. If a camera is rented for 1 or 2 days, it would be logical to rent it from Murphy's.

B. If a camera is needed for more than 3 days, it would make sense to rent it from Allied rental.

C. Yes, if a camera is rented for 3 days both rentals charge the same money.

C. If you were need a camera for 3 days, you would have to pay $135 for both stores.

<u>Step-by-step explanation:</u>

Step 1; Murphy's camera costs $30 to rent and an additional $35 for each day of rental. So the equations are

y = $30 + (x × $35), where y is total cost and x is the number of days rented.

So for x = 1, y = $30 + (1 × $35) = $30 + $35 = $65

So for x = 2, y = $30 + (2 × $35) = $30 + $70 = $100

So for x = 3, y = $30 + (3 × $35) = $30 + $105 = $135

So for x = 4, y = $30 + (4 × $35) = $30 + $140 = $170

So for x = 5, y = $30 + (5 × $35) = $30 + $175 = $ 205.

Step 2; Allied rental costs $45 to rent and a $30 for each day of rental. So the equations are as follows

y = $45 + (x × $30), where y is total cost and x is the days rented

So for x = 1, $45 + (1 × $30) = $45 + $30 = $75

So for x = 2, $45 + (2 × $30) = $45 + $60 = $105

So for x = 3, $45 + (3 × $30) = $45 + $90 = $135

So for x = 4, $45 + (4 × $30) = $45 + $120 = $165

So for x = 5, $45 + (5 × $30) = $45 + $150 = $195

Step 3; Comparing both prices over 5 days. Murphy's is cheaper for until 2 days. On day 3 both the rentals cost the same but after day 4, allied rentals is the better option.

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Bab needs help with mafs
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The 4th option

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Ramiro is 3/10 as tall as the flagpole. The flagpole is 5/9 as tall as the nearby tree. The tree is 32 2/5 feet tall. How tall i
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x-\ Ramiro's\ height\\&#10;y-\ Flapole's\ height\\&#10;z-\ nearby\ tree\\\\&#10;x=\frac{3}{10}y\\&#10;y=\frac{5}{9}z \\z=32\frac{2}{5}\\\\\y=\frac{5}{9}*32\frac{2}{5}=\frac{5}{9}*\frac{162}{5}=18\\\\&#10;x=\frac{3}{10}*18=5,4\\\\&#10;Ramiro\ is\ 5,4\ feet\ tall.
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