Answer:
C)
<h3>
log(117.50 / (117.50 - 2050(0.012) ) / log(1+0.012 ) </h3>
Step-by-step explanation:
Formula to calculate compounded monthly payments
A = R( (1-(1+r)^-n) / r)
where
r = 0.14/12
= 0.012
A = 2050
R = 117.50
n =no. of payments
2050 = 117.50 (1 - (1 + 0.012)^-n / 0.012)
cross multiplication
2050 (0.012) / 117.50 = 1 - (1 + 0.012)^-n
1 on other side
(2050 (0.012) / 117.50) - 1 = - (1+0.012)^-n
eliminating minus sign
1 - (2050 (0.012) / 117.50) = (1+0.012)^-n
LCM
(117.50 - 2050(0.012) ) / 117.50 = (1 + 0.012)^-n
power in negative
(117.50 - 2050(0.012) ) / 117.50 = 1 / (1+0.012)^n
reciprocal
117.50 / (117.50 - 2050(0.012) ) = (1+0.012)^n
taking log
log(117.50 / (117.50 - 2050(0.012) ) = log(1+0.012)^n
Answer
log(117.50 / (117.50 - 2050(0.012) ) = n log(1+0.0120)
<h3>
log(117.50 / (117.50 - 2050(0.012) ) / log(1+0.012 ) = n</h3>
17 goats in the barn and 8 go outside.
9 goats are still in the barn
because seventeen minus eight = nine
Points: (0,4) and (2,-3)
Find slope: (-3-4)/(2) = -7/2
4 = -7/2(0) + b, b = 4
Equation: y = -7/2x + 4
The answer is 0. easy peezy bro
This appears to be about rules of exponents as much as anything. The applicable "definitions, identities, and properties" are
i^0 = 1 . . . . . as is true for any non-zero value to the zero power
i^1 = i . . . . . . as is true for any value to the first power
i^2 = -1 . . . . . from the definition of i
i^3 = -i . . . . . = (i^2)·(i^1) = -1·i = -i
i^n = i^(n mod 4) . . . . . where "n mod 4" is the remainder after division by 4
1. = -3^4·i^(3·2+0+2·4) = -81·i^14 =
812. = i^((3-5)·2+0 = i^-4 =
13. = -2^2·i^(4+2+2+(-1+1+5)·3+0) = -4·i^23 =
4i4. = i^(3+(2+3+4+0+2+5)·2) = i^35 =
-i