Answer:
33-28=5
Step-by-step explanation:
hope this helps
A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
Answer:
it will option D 100degree bcz of corresponding angle property
Hello:
(poq)(x) = p(q(x))= p(x-3) = 2(x-3)²-4(x-3) = 2(x²-6x+9)-4(x-3)
(poq)(x) = 2x²-12x+18-4x+12
(poq)(x) = 2x²-16x+30... (answer : C )
yea this is a tough one it wouldn't even have a full number t would be decimals
