Umm if u factor it u get
-3(x+3)
The function
... y = 1/x
has derivative
... y' = -1/x²
which has no zeros. It is undefined at x=0, the only critical point. The derivative is negative for all values of x, so the function is decreasing everywhere in its domain.
Your function
... y = (x+1)/(x-3)
can be written as
... y = 1 +4/(x-3)
which is a version of y = 1/x that has been vertically scaled by a factor of 4, then shifted 1 unit up and 3 units to the right. Shifting the function to the right means x=3 is excluded from the domain (and the interval on which the function is decreasing).
The critical point is x=3.
The function is decreasing on (-∞, 3) ∪ (3, ∞), increasing nowhere.
Answer:
x = 10/27
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
9/5x = 2/3
<u>Step 2: Solve for </u><em><u>x</u></em>
- Divide both sides by 9/5: x = 10/27
<u>Step 3: Check</u>
<em>Plug in x to verify it's a solution.</em>
- Substitute: 9/5(10/27) = 2/3
- Multiply: 90/135 = 2/3
- Simplify: 2/3 = 2/3
And we have our final answer!
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