Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Then, the answer is 2x^2 + 8x -5
Collect like terms and you'll get -2 - 3(a - b)
Answer:
16 +88i
Step-by-step explanation:
8 x (11i + 2 ) =
Distribute
8*11i + 8*2
88i +16
Writing in the proper form
16 +88i
Let's factor the top and the bottom.
Top factors 4x + 20 = 4(x + 5)
Bottom x^2 + 2x - 15 = (x + 5)(x - 3)
The gcf is the largest value that will go into both the top and the bottom. In our problem the ONLY thing that will go into top and bottom is x + 5 so that is your GCF. (c)
