Answer:
B
Step-by-step explanation:
Givens
a^2 + b^2 = c^2
a = 4x
b = x + 2
c = 3x + 4
Solution
(4x)^2 + (x + 2)^2 = (3x + 4)^3 Remove all the brackets.
16x^2 + x^2 + 4x + 4 = 9x^2 + 24x + 16 Collect like terms on the left
17x^2 + 4x + 4 = 9x^2 + 24x + 16 Subtract the terms on the right
8x^2 - 20x - 12 = 0
This factors into
(4x - 12)(2x + 1)
There are 2 answers
4x - 12 = 0
4x = 12
x = 12/4
x = 3
or
2x + 1 = 0
2x = - 1
x = - 1/2
You have to look at x = -1/2 carefully. The problem is that 4x = 4*(-1/2) = - 2 which is not possible in Euclidean Geometry.
So the only answer is x = 3
Answer:
(-6) - 7 and -6 - (-4)
Step-by-step explanation:
you have to find the rate of change.
this equals -13/4=3.25
Answer:
2
Step-by-step explanation:
the one which is near to x
Answer:
1/114 or 0.008772
Step-by-step explanation:
I am not very sure, my answer seems unlikely, but here's what I think:
There are 20 jerseys in the box to begin with, and 5 medium jerseys that you can have.
Therefore, the probability of you randomly grabbing a medium sized jersey is 5/20 or 1/4.
After taking out one medium sized jersey, there are 19 jerseys in the box and 4 medium jerseys you can pick from.
The probability of you randomly grabbing a medium sized jersey is 4/19.
After taking out another medium sized jersey, there are 18 jerseys left in the box and 3 medium jerseys you can pick from.
The probability of you randomly grabbing a medium sized jersey is 3/18.
To get the answer, you do 1/4 * 4/19 * 3/18, and get 1/114, or 0.00877192982.
If you round that to the nearest millionth, it's 0.008772
Don't judge me, it might not be correct.
First, you need to find the derivative of this function. This is done by multiplying the exponent of the variable by the coefficient, and then reducing the exponent by 1.
f'(x)=3x^2-3
Now, set this function equal to 0 to find x-values of the relative max and min.
0=3x^2-3
0=3(x^2-1)
0=3(x+1)(x-1)
x=-1, 1
To determine which is the max and which is the min, plug in values to f'(x) that are greater than and less than each. We will use -2, 0, 2.
f'(-2)=3(-2)^2-3=3(4)-3=12-3=9
f'(0)=3(0)^2-3=3(0)-3=0-3=-3
f'(2)=3(2)^2=3(4)-3=12-3=9
We examine the sign changes to determine whether it is a max or a min. If the sign goes from + to -, then it is a maximum. If it goes from - to +, it is a minimum. Therefore, x=-1 is a relative maximum and x=1 is a relative miminum.
To determine the values of the relative max and min, plug in the x-values to f(x).
f(-1)=(-1)^3-3(-1)+1=-1+3+1=3
f(1)=(1)^3-3(1)+1=1-3+1=-1
Hope this helps!!
