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4 years ago

How do I solve 3x (x-9)

Mathematics

2 answers:

tiny-mole [99]4 years ago

5 0

Well x stands for an unknown number. So lets say the value of x is 11 you would do 11=9 3x 11 and then multiply 33 x 2

Svetradugi [14.3K]4 years ago

5 0

3x(x-9)

3x^2-27x << Is the answer :) by multiply 3x to x and -9

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Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers

slamgirl [31]

Answer:

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

Step-by-step explanation:

Let be $\vec u = (2,-3)$ , its unit vector is determined by following expression:

$\hat {u} = \frac{\vec u}{\|\vec u \|}$

Where $\|\vec u \|$ is the norm of $\vec u$ , which is found by Pythagorean Theorem:

$\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}$

$\|\vec u\| = \sqrt{13}$

Then, the unit vector is:

$\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)$

$\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

6 0

3 years ago

2w + 7 = 2(w + 5) - 8

BARSIC [14]

Answer:

no solution

Step-by-step explanation:

2w + 7 = 2(w + 5) - 8

Distribute

2w+7 = 2w+10-8

Combine like terms

2w+7 = 2w+2

Subtract 2w from each side

7 = 2

This is never true so there is no solution

7 0

3 years ago

Read 2 more answers

2) Juan had $622 in his checking account. He deposited a check for $180, and $100

adoni [48]

Answer:

867

Step-by-step explanation:

622+180+100=902

902-35=867

3 0

3 years ago

1 /2 + 3/ 4 ÷ 1/3 –1( they are fractions)

marysya [2.9K]

Answer:

2 2/4

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

3/28 of the animals are birds. 4/15 are birds of prey. What fraction of the animals are birds of prey.

vova2212 [387]

Let's call animals "a", and birds "b", birds of prey, "p"

so, b= $\frac{3}{28} a$

and p= $\frac{4}{15} b$
what;s the relation of p to a?

we substitude b into the last one:

and p= $\frac{4}{15}* \frac{3}{28} a$
so:
p= $\frac{4*3}{15*28} a$

p= $\frac{4*1}{5*28} a$

p= $\frac{1*1}{5*7} a$

p= $\frac{1*1}{35} a$

which is the answer!

7 0

3 years ago