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LenKa [72]
4 years ago
5

What's 23 divided by 186

Mathematics
1 answer:
egoroff_w [7]4 years ago
3 0
0.123655913978495
Hope this helps :))
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Vedmedyk [2.9K]

Answer:

angle 4

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP ME WITH THIS
Nataly [62]

Answer:4/10

Step-by-step explanation:

6 0
3 years ago
26. Higher Order Thinking Explain how<br>you know 437,160 is greater than 43,716.​
aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

Locate the decimal point.

Count to the left of the decimal point.

The number with the most number of digits is larger than the number with fewer digits.

437160 has six digits.

It is 10 times bigger then

43716 which only has 5 digits.

5 0
3 years ago
The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt
Marizza181 [45]

Answer:

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

L=w+2

now, we can find area

A=L\times W

now, we can plug it

A=(w+2)\times w

A=w^2+2w

we are given area =6

so, we can set it equal

and then we can solve for w

w^2+2w=6

w^2+2w-6=0

we can use quadratic formula

ax^2+bx+c=0

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}

w=-1+\sqrt{7},\:w=-1-\sqrt{7}

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

7 0
4 years ago
Hopefully someone is going to know this
Reptile [31]

Answer:

The correct answer would be C

Step-by-step explanation:

I hope this helps, if it doesn't then just message me and ill be more than happy to help :)

8 0
2 years ago
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