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Shtirlitz [24]
3 years ago
8

Four microprocessors are randomly selected from a lot of 100

Mathematics
1 answer:
ira [324]3 years ago
7 0

Answer:

Step-by-step explanation:

From the set of 100 with 10 defective microprocessors, the probability of picking a defective one is;

10/100 = 1/10

From the set of 99 remaining and 9 defective microprocessors, the probability of picking a defective one is;

9/99 = 1/11

From the set of 98 remaining and 8 defective microprocessors, the probability of picking a defective one is;

8/98 = 4/49

From the set of 97 remaining and 7 defective microprocessors, the probability of picking a defective one is;

7/97

Adding all 4 probabilities together, we get;

1/10 + 1/11 + 4/49 + 7/97 = 0.345 or 34.5%

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What Is the nth term ruld of the quadratic sequence -5,-4,-1,4,11,20,31
nordsb [41]
-5   - 4    -1    4     11    20    31   subtracting:-
   1       3     5    7      9      11      subtractiing:-    
       2      2     2    2      2

second row is 2 so the rule will contain n^2

so we can write the series as n^2 - 6 , n^2 - 8 , n^2 - 10 etc

the  numbers are in arithmetical sequence with  a1 = 6 and d = -2

so nth term  of our sequence is n^2 - a1 + (n - 1)d = n^2 -2n - 6 + 2
  
  = n^2 - 2n - 4   Answer
 
 
 
     
3 0
3 years ago
Need help asap :) they said the text was too short so don't mind this
Elis [28]

Answer:

try 63

Step-by-step explanation:

14×9=126

126÷2=63

5 0
4 years ago
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Which is the graph of f(x) = 5(2)x?
Yuliya22 [10]
Slope:-2
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Find the area under the standard normal distribution curve between z = –2.05 and z = 2.05.
den301095 [7]
\mathbb P(-2.05
3 0
3 years ago
Please help me with this math!
wel

Answer:

Please check the explanation.

Step-by-step explanation:

Given the polynomial function

f\left(x\right)\:=x^3+2x^2-16x-32

Let us determine the factors by solving

\:\left0\right\:=x^3+2x^2-16x-32\:

\left(x+2\right)\left(x+4\right)\left(x-4\right)=0

Using the zero factor principle:

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+2=0\quad \mathrm{or}\quad \:x+4=0\quad \mathrm{or}\quad \:x-4=0

Thus, (x+2) (x+4) and (x-4) are the factors of the polynomial function.

Therefore,

YES

  • (x+2)
  • (x+4)
  • (x-4)

And (x-2) (x+6) are not the factors of the polynomial function.

Therefore,

YES

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  • (x+6)
3 0
3 years ago
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