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4 years ago

Find the measure of each side of angle abc with vertices a(-1,5) b(6,1) and c(2,-6)

Mathematics

1 answer:

Alex17521 [72]4 years ago

5 0

Answer:

√65,√65 and √129

Step-by-step explanation:

To find the measure of each side of a triangle, we use the distance formula to get it.

The distance Formula is given as:

Distance between two points = √[x2-x1]² + [y2-y1]²

A= (-1, 5), B=(6,1), C=(2,-6)

Going by the distance formula:

Distance AB is given as:

AB= √[6-(-1)]² + [1-5]²

AB= √49 + 16 = √65

Distance BC is given as:

BC= √[2-6]² + [-6-1]²

BC= √16 + 49 = √65

Distance AC ia given as:

AC= √[2-(-1)]² + [-6-5]²

AC= √3² + 11² = √129

Since two sides are equal, the triangle in question is an isosceles triangle.

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Find the measure of each side of angle abc with vertices a(-1,5) b(6,1) and c(2,-6)​

Find the measure of each side of angle abc with vertices a(-1,5) b(6,1) and c(2,-6)