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Ilya [14]
3 years ago
14

On a coordinate plane, triangle G H J has points (1, 1), (4, 1), (4, 5).

Mathematics
1 answer:
CaHeK987 [17]3 years ago
7 0

Answer:

the answer is 6 sq units

Step-by-step explanation:

if it is correct pls give me the brainlest

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I need help plz
shusha [124]

The solution for given linear equation systems is (3,-4).

Option: C

<u>Step-by-step explanation:</u>

The given equations are 5x+3y=3 and x+y= -1.

Let us isolate x value from equation 5x+3y=3.

5x = 3-3y.

x=\frac{3-3y}{5}.

Substitute this x value in equation x+y= -1.

\frac{3-3y}{5}+y=-1.

After taking LCM for the denominator,

\frac{3-3y+5y}{5}= -1.

3-3y+5y=-5.

2y=-8.

y=-4.

For x=\frac{3-3y}{5} substitute the y value.

x=\frac{3-3(-4)}{5}.

x=\frac{3+12}{5}.

x=\frac{15}{5}.

x=3.

∴ The solution is (3,-4).

8 0
3 years ago
What is the area of a triangle with vertices at (−4, 1) , ​ (−7, 5) ​ , and ​ (0, 1) ​?
artcher [175]
The answer to this is 8.
3 0
3 years ago
Write ‒6x^2 + 13x ‒ 6 as the product of two binomials.
VLD [36.1K]
Should be (x-1.5)(x-2/3)
5 0
3 years ago
How do you do this question?
Molodets [167]

Answer:

C. y₂ = (1 + (t/n))²

Step-by-step explanation:

yₙ₊₁ = yₙ + Δt F(tₙ, yₙ)

yₙ₊₁ = yₙ + Δt yₙ

yₙ₊₁ = yₙ + (t/n) yₙ

When n=0:

y₁ = y₀ + (t/n) y₀

y₁ = 1 + (t/n)

When n=1:

y₂ = y₁ + (t/n) y₁

y₂ = 1 + (t/n) + (t/n) (1 + (t/n))

y₂ = 1 + (t/n) + (t/n) + (t/n)²

y₂ = 1 + 2(t/n) + (t/n)²

y₂ = (1 + (t/n))²

4 0
3 years ago
Help please I forgot
Gre4nikov [31]

Answer:

.3636363636363636363636363636363636363...so on so forth.

Step-by-step explanation:

repeating

8 0
3 years ago
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