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Ilya [14]
3 years ago
14

On a coordinate plane, triangle G H J has points (1, 1), (4, 1), (4, 5).

Mathematics
1 answer:
CaHeK987 [17]3 years ago
7 0

Answer:

the answer is 6 sq units

Step-by-step explanation:

if it is correct pls give me the brainlest

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Which number is a common multiple of 3 and 4?<br> A) 8<br> B) 14<br> C) 32<br> D) 48
Luba_88 [7]

Answer:

LCM of 3 and 4 is 12

Step-by-step explanation:

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Which integer is closest to 0 on the number line?
IrinaVladis [17]

An integer is close to zero if it is "small".

By small, we mean that it is small in absolute value. In fact, for any given distance d, there are two integers that are d units away from zero: d and -d.

So, for example, -6 is close to zero than 8, because -6 is six units away from zero, while 8 is eight units away from zero.

So, the answer is B, -8, because it is 8 units away from zero. The other options A, C and D are, respectively, 12, 10 and 14 units away from zero.

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3 years ago
Let the equation C = 2.32 N + 34,180 represent the cost of raising a child, C, on an income, N.
ivanzaharov [21]

Answer:

C = 2.32 N + 34,180

C = 2.32 × 60000 + 34,180

C = 139200 + 34180

C = $173,380

4 0
3 years ago
Please help<br><br>Point____is plotted at -4/5​
musickatia [10]

Answer:

C

Step-by-step explanation:

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8 0
3 years ago
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The rectangle below has an area of 1 8 x 3 18x 3 square meters and a length of 2 x 2 2x 2 meters.
motikmotik

Answer:

\text{The width of rectangle}=9x\text{ meters}

Step-by-step explanation:

We have been given that the rectangle has an area of 18x^3 square meters and a length of 2x^{2}. We are asked to find the width of rectangle.

Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.

\text{Area of rectangle}=\text{Width of rectangle *Length of the rectangle}

\frac{\text{Area of rectangle}}{\text{Length of rectangle}}=\frac{\text{Width of rectangle *Length of the rectangle}}{\text{Legth of rectangle}}

\text{The width of rectangle}=\frac{\text{Area of rectangle}}{\text{Length of rectangle}}

Upon substituting our given values in above formula we will get,

\text{The width of rectangle}=\frac{18x^3\text{ meter}^2}{2x^2\text{ meters}}

\text{The width of rectangle}=\frac{9x^3\text{ meters}}{x^2}

Using exponent rule for quotient \frac{a^m}{a^n}=a^{m-n} we will get,

\text{The width of rectangle}=9x^{3-2}\text{ meters}

\text{The width of rectangle}=9x^{1}\text{ meters}=9x\text{ meters}

Therefore, width of our given rectangle will be 9x meters.

3 0
3 years ago
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