Answer:
0.45 ft/min
Step-by-step explanation:
Given:-
- The flow rate of the gravel,
- The base diameter ( d ) of cone = x
- The height ( h ) of cone = x
Find:-
How fast is the height of the pile increasing when the pile is 10 ft high?
Solution:-
- The constant flow rate of gravel dumped onto the conveyor belt is given to be 35 ft^3 / min.
- The gravel pile up into a heap of a conical shape such that base diameter ( d ) and the height ( h ) always remain the same. That is these parameter increase at the same rate.
- We develop a function of volume ( V ) of the heap piled up on conveyor belt in a conical shape as follows:
- Now we know that the volume ( V ) is a function of its base diameter and height ( x ). Where x is an implicit function of time ( t ). We will develop a rate of change expression of the volume of gravel piled as follows Use the chain rule of ordinary derivatives:
- Determine the rate of change of height ( h ) using the relation developed above when height is 10 ft:
Answer:
<BAR ≅<CAR
Step-by-step explanation:
Just took the test
Answer:
27
Step-by-step explanation:
-7*-3/5 * 45/7
-7/1 * -3/5 =21/5 * 45/7 = 3/1 *9/1=27
Answer:
x=4
Step-by-step explanation:
Let's solve your equation step-by-step.
−x=2−3x+6
Step 1: Simplify both sides of the equation.
−x=2−3x+6
−x=2+−3x+6
−x=(−3x)+(2+6)(Combine Like Terms)
−x=−3x+8
−x=−3x+8
Step 2: Add 3x to both sides.
−x+3x=−3x+8+3x
2x=8
Step 3: Divide both sides by 2.
2x/2 = 8/2
x=4