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Simora [160]
3 years ago
8

There are a total of 48 students in grade 10 charity.Twenty are boys and 28 are girls.S uppose that a team of 3 students is form

ed such that it is composed of a team leader,a secretary,and a spokesperson.What is the probability that a team formed is composed of a girl secretary?
Mathematics
1 answer:
zubka84 [21]3 years ago
4 0

Answer:

the answer is still (28*47*46)/(48*47*46) = 7/12.

Step-by-step explanation:

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Solve it (2⋅3) ^2−5 ^2=
sattari [20]

Answer:

11

Step-by-step explanation:

(2×3)^2 = 6^2 = 36

5^2 = 25

(2×3)^2 - 5^2 = 36 - 25 = 11

5 0
3 years ago
Read 2 more answers
Im so confused. :/ Anyone?
ArbitrLikvidat [17]
First one = 9x3=27

Second one 12x9=108

3rd one = 3x4=12
 
Idk what that last one is
7 0
4 years ago
Tell me how to shade the area on the grid that shows 7/8x3/4
viva [34]
If the grid is an 8x8: 

To solve this we need to convert 3/4 into a fraction x/8 so that they have the same denominator.

To do this we can set a porportion and find a common denominator. 4 x 2 = 8 so the common denominator would be 8 and the rule would be x 2 so 4 x 2 = 8 and 3 x 2 = 6

So we get 7/8 and 6/8

From top to bottom shade 7 spaces in a row

From left to right shade 6 spaces in a row

Fill in the spaces in between to make a square

I hope this helps!
8 0
3 years ago
Read 2 more answers
HELP ME WITH THIS QUESTION PLZZZZZZZZZZZ, ALSO PLEASE SHOW UR WORK I NEED HELP I DON'T UNDERSTAND THISSSSSS
Ann [662]

Answer: Jon has the best rate

Step-by-step explanation:

3 0
3 years ago
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 450 gram setting. It
Arturiano [62]

Answer:

Test statistic = -2.25

P-value = 0.0199

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 450 gram

Sample mean, \bar{x} = 441 grams

Sample size, n = 16

Alpha, α = 0.05

Sample variance = 256

\sigma^2 = 256\\\sigma = \sqrt{256} = 16

First, we design the null and the alternate hypothesis

H_{0}: \mu = 450\text{ grams}\\H_A: \mu < 450\text{ grams}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{441 - 450}{\frac{16}{\sqrt{16}} } = -2.25

Now,

Degree of freedom =

=n-1 = 16-1=15

We can calculate the p-value from the table as:

P-value = 0.0199

Conclusion:

Since the p-value is smaller than the significance level we fail to accept the null hypothesis and reject it.

Thus, there is enough evidence to support the claim that the machine is under filling the bags .            

5 0
3 years ago
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