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Jobisdone [24]
3 years ago
12

The value of loga (30a)^3 is

Mathematics
1 answer:
postnew [5]3 years ago
8 0
Part 1 of the solution.

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Awnser me pkeaeeeeeeeeee
postnew [5]

Answer:

46.01

Step-by-step explanation:

i.e sum of all the purchases + 7% of the total purchase.

3 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
Helga [31]

Answer:

\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

Step-by-step explanation:

Rn(x) →0

f(x) = 10/x

a = -2

Taylor series for the function <em>f </em>at the number a is:

f(x) =  \sum^\infty_{n=0} \frac{f^{(n)}(a)}{n!} (x - a)^n

f(x) = f(a) + \frac{f'(a)}{1!}(x-a)+\frac{f"(a)}{2!} (x-a)^2 + ... ............ equation (1)

Now we will find the function <em>f </em> and all derivatives of the function <em>f</em> at a = -2

f(x) = 10/x            f(-2) = 10/-2

f'(x) = -10/x²         f'(-2) = -10/(-2)²

f"(x) = -10.2/x³      f"(-2) = -10.2/(-2)³

f"'(x) = -10.2.3/x⁴     f'"(-2) = -10.2.3/(-2)⁴

f""(x) = -10.2.3.4/x⁵    f""(-2) = -10.2.3.4/(-2)⁵

∴ The Taylor series for the function <em>f</em> at a = -4 means that we substitute the value of each function into equation (1)

So, we get \sum^\infty_{n=0} - \frac{10(x+2)^n}{2^{n+1}} Or \sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

4 0
3 years ago
Which is bigger? 1.27 or 1 1/3?
uranmaximum [27]
11/3 is bigger 1.27 because when you do 11/3 you get 3.66666666666666666667 which is clearly bigger than 1.27 so like I said 11/3 is bigger than 1.27.
6 0
3 years ago
Read 2 more answers
Solve: -2x - 5 = -3 <br> plz help me hurry
lord [1]

Answer:

x=-1

Step-by-step explanation:

-2x - 5 = -3

add 5 to both sides

-2x = 2

divide both sides by -2

x = -1

8 0
3 years ago
Read 2 more answers
16x - 5y = -33<br> 16x + y = -51
timofeeve [1]
Use the elimination process
6 0
3 years ago
Read 2 more answers
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