The 3-digit number is 132
<h3>How to determine the
3-digit number?</h3>
The given parameters are:
- Number of digits = 3
- Sum of digits = 6
- No 0s in the number
- No repeated digit
The first highlight above implies that the number can be any of 100 to 999
The other highlights imply that the no digit can appear repeatedly, the highest digit in the number is 3, and the number must end with 2.
So, we have:
X32
The first digit is the smallest.
1 is smaller than 3 and 2.
So, we have
132
Hence, the 3-digit number is 132
Read more about digits and numbers at:
brainly.com/question/26856218
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Answer:
Hi!
Your answer is:
25d
Since we aren't aware of how many days he is working, we substitute a variable (d) in for it!
I hope this helps!
Answer:
√3 is irrational
Step-by-step explanation:
The location of the third point of a triangle can be found using a rotation matrix to transform the coordinates of the given points.
<h3 /><h3>Location of point C</h3>
With reference to the attached figure, the slope of line AC is √3, an irrational number. This means the line AC <em>never passes through a point with integer coordinates</em>. (Any point with integer coordinates would be on a line with rational slope.)
<h3>Equilateral triangle</h3>
The line segments making up an equilateral triangle are separated by an angle of 60°. If two vertices are on grid squares, the third must be a rotation of one of them about the other through an angle of 60°. The rotation matrix is irrational, so the rotated point must have irrational coordinates.
The math of it is this. For rotation of (x, y) counterclockwise 60° about the origin, the transformation matrix is ...
![\left[\begin{array}{cc}\cos(60^\circ)&\sin(60^\circ)\\-\sin(60^\circ)&\cos(60^\circ)\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{c}x'\\y'\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Ccos%2860%5E%5Ccirc%29%26%5Csin%2860%5E%5Ccirc%29%5C%5C-%5Csin%2860%5E%5Ccirc%29%26%5Ccos%2860%5E%5Ccirc%29%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%27%5C%5Cy%27%5Cend%7Barray%7D%5Cright%5D)
Cos(60°) is rational, but sin(60°) is not. For any non-zero rational values of x and y, the sum ...
cos(60°)·x + sin(60°)·y
will be irrational.
As in the attached diagram, if one of the coordinates of the rotated point (B) is zero, then one of the coordinates of its image (C) will be rational. The other image point coordinate cannot be rational.
Answer:
see the explanation
Step-by-step explanation:
First way
we know that
The sum of the interior angles of a triangle must be equal to 180 degrees
so
In this problem
37+97+134 > 180
therefore
At least one of Franklin's measures is incorrect
Second way
we know that
A triangle can only have at most one obtuse internal angle.
In this problem the triangle has two obtuse internal angles
Remember that an obtuse angle is an angle greater than 90 degrees
therefore
At least one of Franklin's measures is incorrect
17 and 4 multiply to 68 and have a difference of 13