Taking the same test right now....I think the answer is 4.5. Hope that helps!
<span>The sections that it is in are
Classifying Quadrilaterals
Properties of Parallelograms
Special Parallelograms
Trapezoids and Kites
Placing Figures in the Coordinate Plane</span>
The answers for the exercise shown above are the second option, the third option, the fifth option and the sixth option, which are:
2) <span>Distribute 2 to 9.7 and −4.8x.
3) Combine 3.4 and 19.4.
5) Substract 22.8 from both sides.
6) Divide both sides by −9.6
The steps are shown below:
</span><span>3.4+2(9.7-4.8x)=61.2</span>
3.4+19.4-9.6x=61.2
22.8-9.6x=61.2
228-22.8-9.6x=61.2-22.8
-9.6x=38.4
-9.6x/-9.6=38.4/-9.6
x=-4
2L + 2W = 48
L= 15 feet
substitute the given value to the formula provided.
2(15) + 2W = 48
multiply 2 by 15
30 + 2W = 48
use the subtraction property of equality to cancel the value 30 on the left side.
30 - 30 + 2W = 48 - 30
cancel 30 on the left side leaving 2W while subtract 30 from 48.
2W = 18
divide both sides to get the value of the width.
2W/2 = 18/2
W = 9ft this is the final answer.
Answer:
Q + 601 = -104
Subtract 601 from both sides
Q = -705
