Answer: $76,244.51
Step-by-step explanation:
You need to use the compound interest formula here.
First of all however, you need to convert the terms to monthly figures because the interest is compounded monthly.
4% in months = 4 / 12 = 4/12%
6 years = 6 * 12 = 72 months
Now use the compound interest formula:
= Amount * (1 + rate) ^ number of years
= 60,000 * ( 1 + 4/12%) ⁷²
= $76,244.51
The probabilities of at least 10 are repairable is 1/3. and probabilities of from 3 to 8 are repairable is 1/5*8/15 and probabilities of exactly 5 are repairable is 1/3.
According to the statement
we have given that If 15 actuators have failed and we have to find the probabilities on some conditions.
we know that the formula of probabilities is
probability = possible outcomes / total outcomes
So,
- at least 10 are repairable = 1 - (10 are not repairable)
at least 10 are repairable = 1 - 10/15
at least 10 are repairable = (15 - 10)/15
at least 10 are repairable = (5)/15
at least 10 are repairable = 1/3
- from 3 to 8 are repairable = 3/15 *8/15
from 3 to 8 are repairable = 1/5 *8/15
- exactly 5 are repairable = 5/15
exactly 5 are repairable = 1/3
These are the probabilities of the given conditions.
So, The probabilities of at least 10 are repairable is 1/3. and probabilities of from 3 to 8 are repairable is 1/5*8/15 and probabilities of exactly 5 are repairable is 1/3.
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Answer:6018
Step-by-step explanation:
Given Sequence

It represent an A.P. with
first term 
common difference 
So sum of 51 term
![S_n=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
![S_{51}=\frac{51}{2}\times [2\times (-282)+(51-1)16]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B2%5Ctimes%20%28-282%29%2B%2851-1%2916%5D)
![S_{51}=\frac{51}{2}\times [-564+800]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B-564%2B800%5D)
![S_{51}=\frac{51}{2}\times [236]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B236%5D)


Answer:
Let Marshall's salary be
S
m
Let Jim's salary be
S
j
Let the count in years be
n
S
m
=
$
36000
+
4000
n
S
j
=
$
51000
+
1500
n
Set
S
m
=
S
j
For convenience lets drop the $ symbol
⇒
36000
+
4000
n
=
51000
+
1500
n
Subtract
1500
n
and
36000
from both sides
4000
n
−
1500
n
=
51000
−
36000
2500
n
=
15000
Divide both sides by 2500
n
=
15000
2500
=
150
25
=
6
Step-by-step explanation: