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JulijaS [17]
3 years ago
10

Plz help will mark brainliest

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
4 0
Answer:1/3

Y2-y1/x2-x1

3-1/9-6=2/6=1/3
nikklg [1K]3 years ago
4 0
ANSWER: 1/3

to find slope, solve (y2-y1)/(x2-x1)

(3-1)/(9-3) = 2/6 = 1/3

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On number 5 how do you explain how you found your answer
aivan3 [116]

30 girls , 12 were selected

40 boys, 16 were selected

We can simplify these down by finding the Greatest Common Factor in both girls and boys:

30:12 .... 15:6 .... 1 : 2.5 30/12 .... 15/6 .... 2.5

40:16 .... 20:8 .... 1 : 2.5 OR 40/16 .... 20/8 .... 2.5

They are equal ratios because their most simplified ratios/fractions are equivalent

8 0
3 years ago
What is the product of a+3 and -2a2+15a+6b2?
ankoles [38]

Answer: -2a^3 + 9a^2 + 45a + 18b^2 + 6ab^2

Step-by-step explanation:

(a + 3) * (-2a^2 + 15a + 6b^2)

We open the brackets with (a + 3)

a ( -2a^2 + 15a + 6b^2) + 3(-2a^2 + 15a + 6b^2)

Opening the brackets

= a * -2a^2 = -2a^3

a * 15a = 15a^2

a * 6b^2 = 6ab^2

3 * -2a^2 = -6a^2

3 * 15a = 45a

3 * 6b^2 = 18b^2

Let's arrange those values weve gotten together ,don't forget the signs each carry

= -2a^3 + 15a^2 + 6ab^2 - 6a^2 + 45a + 18b^2

Collect the like terms

= -2a^3 + 15a^2 - 6a^2 + 6ab^2 + 45a + 18b^2

= -2a^3 + 9a^2 + 6ab^2 + 45a + 18b^2

4 0
4 years ago
Read 2 more answers
Help me solve this question
irga5000 [103]
The correct answer is 1.

So, circle the 0 after the equals sign because the equation does not equal 0.

Anything raised by the power of 0 is 1.

This is known as the zero exponent rule :)
8 0
3 years ago
What is the slope of a line that passes through (–14,13) and (7,0)?
Evgesh-ka [11]
The answer would be D.-13/21
7 0
4 years ago
Read 2 more answers
Suppose you do an analysis of the starting salaries of 100 recent Lehman graduates. You find that the average starting salary is
madreJ [45]

Answer:

a) (59180,60820)

b) (59020,60980)        

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $60,000

Standard Deviation, σ = $5,000

Sample size, n = 100

a) 90% critical values

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.10} = 1.64

60000 \pm 1.64(\frac{5000}{\sqrt{100}} ) = 60000 \pm 820 = (59180,60820)

b) 95% critical values

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

60000 \pm 1.96(\frac{5000}{\sqrt{100}} ) = 60000 \pm 980= (59020,60980)

5 0
3 years ago
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