Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
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<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
(6, 4, 4, 5, 1, 8, 10, 7, 8, 6, 6, 7, 5, 4, 6)
Lapatulllka [165]
<span>In a stem-and-leaf plot, </span><span>5| 4 means 54</span>
1/12 ÷30 is equal to 1/360 or in decimal form is a repetitive decimal which is .2777777777777777777777....
Answer:
A=3√5
B=11√7
Step-by-step explanation:
5√5-2√5
5-2√5
3√5
B) 8√7+3√7
8+3√7
11√7
D) 65% decrease.
I worked it out by: 268 mill - 94 mill (calculating the difference in money)
then divided that by the original 268 mill, to finally get 0.64925....
And since the money is decreasing, it is a 65% decrease.
Hope this helps, and I think it should be right - but maybe double check in case :)
