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Serga [27]
2 years ago
6

Use the Distance Formula to find the distance between points 1 and 2 on the coordinate plane, rounded to the nearest tenth unit.

Mathematics
1 answer:
Shkiper50 [21]2 years ago
4 0

Answer:

\sf d = 121.0

given:

  • Point 1: (0, 80)
  • Point 2: (95,5)

distance between two points formula:

\sf d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}

using the formula:

\sf d = \sqrt{(95 - 0)^2 + (5-80)^2}

\sf d = \sqrt{9025 + 5625}

\sf d = \sqrt{14650}

\sf d = 5\sqrt{586}

\sf d = 121.0

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Jack ran at 880 ft./min. For the first 10 min. Of the 3 mi. Race before slowing his pace to finish the race with a total time of
Nina [5.8K]

Answer:

Jack ran 704 ft/min during the second half of the race.

Step-by-step explanation:

Here the distance traveled was 3 miles, and the total elapsed time was 20 minutes.  Recall that distance = rate * time, or rate = distance / time.

Find the pace (speed, rate) for the second part of the race.

Here, the total distance was 3 miles and the elapsed time 20 minutes.  Jack's average speed was thus 3/20 miles/minute.  Converting this to feet per minute, we get:

3 mi          5280 ft

------------ * ------------- = 792 ft/min    (Jack's average speed)

20 min        1 mi

Recall that the formula for finding the average of x and y is (x + y) / 2.

(1/2)(880 ft/min  +  p) = 792 ft/min; find p, which represents Jack's pace for the second part of the race.

If (1/2)(880 ft/min  +  p) = 792 ft/min, and we mult. both sides by 2, we get:

880 ft/min + p = 1584 ft/min.

To solve this for p, subtract 880 ft/min from both sides, obtaining:

p = 704 ft/min

Jack ran 704 ft/min during the second half of the race.

3 0
3 years ago
In 1 year, how many more hours of sleep does a giant armadillo get than a platypus?
kumpel [21]

If the given variables are 127 hours of sleep per week for a Giant Armadillo, and 98 hours of sleep per week for a Platypus, to determine which animal gets the most sleep, first multiply the total hours of sleep of each animal per week to the total number of weeks In a year, which is 52. Once you get the answers, which are 6,604 hours of sleep in a year for the Giant Armadillo and 5,096 hours of sleep in a year for a Platypus. You subtract 6,604 and 5,096 together to get the answer, which is 1,508. Therefore we conclude that that the Giant Armadillo has 1,508 hours more hours of sleep than a Platypus in a Year.

6 0
3 years ago
What is the domain of validity for csc theta = 1 / sin theta?
Rashid [163]
De finition\ of\ csc\theta=\frac{1}{sin\theta}\\-----------------------\\therefore\ csc\theta=\frac{1}{sin\theta}\to\frac{1}{sin\theta}=\frac{1}{sin\theta}\\\\the\ denominator\ must\ be\ different\ from\ zero,\ therefore\\\\sin\theta\neq0\iff\theta\neq k\pi\ where\ k\in\mathbb{Z}\\\\Answer:\boxed{D}
4 0
4 years ago
The introduction of ukiyo-e created a demand for products from which country?
RideAnS [48]
The introduction of ukiyo-e created a demand for products from Japan...
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4 years ago
Molly opened a bank account. She deposited $86.50 into her account every month for 20 months. She used $24.50 every month to pay
harkovskaia [24]
First, let's multiply 86.50 by 20 since she deposited $86.50 each month for 20 months.

86.50 * 20 = $1,730

Now, we have to divide this by 24.50 * 20 to find how much out of her $1,730 that she used on singing lessons.

24.50 * 20 = $490

Subtract how much she used for singing lessons from her total amount.

1,730 - 490 = $1,240

Finally, we multiply the amount she has left by 1/4 to find out how much she spent on her summer camp. We can also do this by multiplying 1,240 by 0.25 since 0.25 = 1/4.

1,240 * 0.25 = $310

So, Molly spent $310.00 on her summer camp.
Hope this helped!
7 0
3 years ago
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