All categories

2 years ago

Find the exterior angle of angle c.

Mathematics

1 answer:

Bingel [31]2 years ago

4 0

Answer:

Step-by-step explanation:

This triangle is a polygon. By definition, all the exterior angles of ANY polygon add up to equal 360 degrees. So we add up all the exterior angles and solve for x. That's the first step.

7x - 2 + 9x - 31 + 4x + 33 = 360

Combining like terms gives us

20x + 0 = 360 or simply

20x = 360 so

x = 18

In order to find the value of the angle exterior to angle C, we sub 18 in for x:

7(18) - 2 = 124

You might be interested in

Find the LCD. 2/5, 1/2, and 3/4

harina [27]

Answer:

Step-by-step explanation:

8 0

2 years ago

What is the BEST deal on sugar?

Lana71 [14]

Answer:

Step-by-step explanation:

well if you multiply each of tjem you would only sabe money on c the other choices would cause you to lose money so its c

8 0

2 years ago

The pottery class has 15 pounds of clay. Each student got 1/3 pound of clay to make a plate. How many plates did the students ma

wolverine [178]

15÷1/3= 45 so the students made 45 clay plates

4 0

2 years ago

Write 43 as a sum of powers of 2.<br> (2 Has to be the Base not the exponent)

slamgirl [31]

Answer:

2⁰ + 2¹+ 2⁵ +2³ = 43

Step-by-step explanation:

since 43 is odd, we know 2⁰ or 1 must be one of the sums

43 - 2⁰ = 42

42 - 2¹ = 40

16 = 2⁴

40-2(16) = 40 - 2⁵ = 8

8 = 2³

adding this all together

2⁰ + 2¹+ 2⁵ +2³ = 43

6 0

3 years ago

Given the tables for f & g below, find the following: x f ( x ) g ( x ) 0 9 7 1 4 8 2 3 6 3 5 1 4 7 5 5 1 2 6 6 0 7 0 4 8 2

d1i1m1o1n [39]

$\\(i)\\
\text{We know that the average rate of change of a function f(x) on inerval [a,b] is}\\
\\
f_{avg}=\frac{f(b)-f(a)}{b-a}\\
\\
\text{so using this the average rate of chang of g for x on interval }[3,7] \text{ is}\\
\\
g_{avg}=\frac{g(7)-g(3)}{7-3}\\
\\
=\frac{4-1}{4}\\
\\
=\frac{3}{4}\\
\\
\text{so average rate of change of g on interval [3,7] is }\frac{3}{4}$

$\\(ii)\\ \text{Average rate of chang of f for x on interval }[3,7] \text{ is}\\
\\
f_{avg}=\frac{f(7)-f(3)}{7-3}\\
\\
=\frac{0-5}{4}\\
\\
=\frac{-5}{4}\\
\\
\text{so average rate of change of g on interval [3,7] is }\frac{-5}{4}$

$\\(iii)\\
\text{Since g(4)=5, so we have}\\
\\
f(g(4))=f(5)\\
\\
\text{since the value of f is 1 at x=5. so }\\
\\
f(g(4))=f(5)=1\\
\\
\text{hence we have, }f(g(4))=$ 1

$\\(iv)\\
\text{Since f(3)=5, so we have}\\
\\
g(f(3))=g(5)\\
\\
\text{since the value of g is 2 at x=5. so }\\
\\
g(f(3))=g(5)=2\\
\\
\text{hence we have, }g(f(3))=$ 2

5 0

3 years ago