$\bf -7x-2y=4\implies -2y=7x+4\implies y=\cfrac{7x+4}{-2}\implies y=\cfrac{7x}{-2}+\cfrac{4}{-2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{2}} x-2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{7}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{7}}\qquad \stackrel{negative~reciprocal}{\cfrac{2}{7}}}$

now, what's the slope of a line parallel to that one above? well, parallel lines have exactly the same slope.

5 0

3 years ago

I really need help. ( Intro to limits )

valentina_108 [34]

The answer should be A

6 0

3 years ago

3 posters cost $9.60. At this rate how many posters can you buy with $48

Ksju [112]

About 15 because 9 times 5 = 45 reminder 3 than you add 3 times 5 = 15

3 0

3 years ago