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3 years ago

Zane had 7/8 of a bottle of water left. Anna had 4/8 of a bottle of water left. How much more water did Zane have than Anna?

Mathematics

1 answer:

Shtirlitz [24]3 years ago

8 0

Zane had 3/8 of a bottle of water more than Anna

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Bob need to mix 2 cups of orange juice concentrate with 3.5 cups of water to make orange juice. bob has 6 cups of concentrate. h

USPshnik [31]

3 x 2 = 6 cups of concentrate

3.5 x 3 = 10.5 cups of water

Bob can make 6 cups of orange juice.

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3 years ago

Read 2 more answers

What does the x-intercept sometimes represent in a real world problem

UNO [17]

I think it represents where something is starting from, like something growing up (a chart with rising numbers)

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3 years ago

Help...

PolarNik [594]

Answer: perm will cost $48

Step-by-step explanation:

Let x be cost of haircut

So perm will cost her 2x

x + 2x + 5 = 77

3x = 72

x = 24

Perm will cost 2x24 = 48

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3 years ago

It takes you 45 minutes to clean the fish tank and it takes your sister 30 minutes. how long does it take the two of you working

katen-ka-za [31]

It takes you 45 minutes to clean the fish tank and it takes your sister 30 minutes. how long does it take the two of you working together to clean the fish tank

Answer:

My 1 minute work = $\frac{1}{45}$

My sisters 1 minute work = $\frac{1}{30}$

My and My sister's 1 minute work = $\frac{1}{45}+\frac{1}{30}$

= $\frac{5}{90}$

= $\frac{1}{18}$

$\therefore$ Me and My sister will finish the work in $\frac{18}{1} =18$ minutes

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3 years ago

A sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to

Archy [21]

Answer:

0.2916, 0.1488, 0.0319

Step-by-step explanation:

Given that a sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to have oil added.

Since each trial is independent there is a constant probability for any random car to need oil is 0.10

Let X be the number of cars that need oil

A) Here X is BIN(4,0.1)

$P(X=1) = 4C1(0.1)(0.9)^3 \\= 0.2916$

B) Here X is Bin (8, 0.1)

$P(x=2) = 8C2 (0.1)^2 (0.9)^6\\\\=0.1488$

C) Here X is Bin (20,5)

$P(x=5) = 20C5 (0.1)^5 (0.9)^{15} \\=0.0319$

3 0

3 years ago