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Nikolay [14]
3 years ago
15

The votes for president in a club election were: Smith: 24 Munoz: 32 Park: 20 Find the following ratios and write in simplest fo

rm. Votes for Munoz to Smith : Votes for Park to Munoz : Votes for Smith to total votes : Votes for Smith to Munoz to Park
Mathematics
1 answer:
topjm [15]3 years ago
3 0

Hey there! I'm happy to help!

VOTES FOR MUNOZ TO SMITH

32:24

We see that both have a common factor of 8, so we can divide both by that.

4:3

This is in simplest form.

VOTES FOR PARK TO MUNOZ

20:32

We see that both have a common factor of 4, so we divide both by that.

5:8

This is completely simplified.

VOTES FOR SMITH TO TOTAL VOTES

24+32+20=76

24:76

We see that both have a common factor of 4, so will divide both by that.

6:19

We cannot simplify any more here.

VOTES FOR SMITH TO MUNOZ TO PARK

24:32:20

We can divide these all by four, so let's do that.

6:8:5

This can't be simplified anymore, so it is in simplest form.

Have a wonderful day! :D

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which equation represents an exponential function that passes through the point (2, 80)? f(x) = 4(x)5 f(x) = 5(x)4 f(x) = 4(5)x
pav-90 [236]

we know that

if the exponential function passes through the given point, then the point must satisfy the equation of the exponential function

we proceed to verify each case  if the point (2,80) satisfied the exponential function

<u>case A</u>  f(x)=4(x^{5})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=4(2^{5})=128

128\neq 80

therefore

the exponential function  f(x)=4(x^{5}) not passes through the point (2,80)

<u>case B</u>  f(x)=5(x^{4})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=5(2^{4})=80

80=80

therefore

the exponential function f(x)=5(x^{4}) passes through the point (2,80)

<u>case C</u>  f(x)=4(5^{x})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=4(5^{2})=100

100\neq 80

therefore

the exponential function f(x)=4(5^{x}) not passes through the point (2,80)

<u>case D</u>  f(x)=5(4^{x})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=5(4^{2})=80

80=80

therefore

the exponential function f(x)=5(4^{x}) passes through the point (2,80)

therefore

<u>the answer is</u>

f(x)=5(x^{4})

f(x)=5(4^{x})

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