All categories

3 years ago

Help me will mark brainliest asapppp

Mathematics

1 answer:

kow [346]3 years ago

8 0

Answer:

Between -3 and -2 g(x) decreases, and the same is with B and C so the answer is D.

You might be interested in

Solve the system. 2x + y = −3 −2y = 6 + 4x Write each equation in slope-intercept form.

Fantom [35]

The slope-intercept form:

y = mx + b

m - slope

b - y-intercept

-------------------------------------

2x + y = -3 subtract 2x from both sides

y = -2x - 3

-2y = 6 + 4x

-2y = 4x + 6 divide both sides by (-2)

y = -2x - 3

We have the same equations. Therefore the system of equations is dependent. Has an infinite number of solutions

x ∈ R

y = -2x - 3

7 0

4 years ago

Read 2 more answers

What is 26000 in expanded notation

max2010maxim [7]

20000+6000=26000 hope it helps

3 0

3 years ago

Read 2 more answers

A(-1, 1)b(1, -2)c(0, -4) rotated 270 degrees by the origin

Ilia_Sergeevich [38]

Use the formula (y,-x)
a: (1,1)
b’(-2,-1)
c’(-4,0)

8 0

3 years ago

In a solar system, two comets pass near the sun, which is located at the origin. Comet E is modeled by quantity y plus 16 end qu

Leya [2.2K]

Explanation:

The equation of comet E is given below as

$\frac{(y+16)^2}{400}+\frac{x^2}{144}=1$

The equation of comet H is modelled below as

$\frac{(y+13)^2}{144}-\frac{x^2}{25}=1$

Given, that the Sun is located at the origin.

This is an equation of an ellipse. So, the path traveled by Comet e is an elliptic path.

Comparing with the Standard equation of ellipse: below,we will have

$\frac{(y-k)^2}{b^2}+\frac{(x-h)^2}{a^2}$

Whise center is

$\begin{gathered} center=(h,k) \\ vertices=(h\pm a,0) \end{gathered}$

By comparing coefficient, we will have

$\begin{gathered} a^2=144 \\ a=12 \\ b^2=400 \\ b=20 \\ k=-16 \\ h=0 \\ (h,k)=(0,-16) \end{gathered}$

Hence,

The vertex of comet E will be

$\begin{gathered} (h\pm a,0) \\ (0+12,0),(0-12,0) \\ (12,0),(-12,0) \end{gathered}$

The vertex of comet E is

$(12,0),(-12,0)$

Part C:

It is the foci forboth comets

$\begin{gathered} cometE: \\ c=\sqrt{b^2-a^2} \\ c=\sqrt{400-144} \\ c=\sqrt{256} \\ c=16 \\ \\ For\text{ comet F:} \\ c=\sqrt{a^2-b^2} \\ c=\sqrt{144+25} \\ c=\sqrt{169} \\ c=13 \end{gathered}$

Hence,

The foci will be

$\begin{gathered} (16\pm16,0) \\ cometE \\ (0,0),(32,0) \\ cometF: \\ (13\pm13,0) \\ (0,0),(26,0) \end{gathered}$

5 0

1 year ago

Write an equation for each line

Virty [35]

The answer will be c

4 0

3 years ago