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vazorg [7]
3 years ago
12

What 76.2 divided by 18.4

Mathematics
2 answers:
vova2212 [387]3 years ago
7 0
The answer is 4.16 why don't you just punch it in ur calculator?
vampirchik [111]3 years ago
5 0

4.141304347826087

 That's what I got when I did that

You might be interested in
Not sure if any of this is correct, but it’s what I got so far
Irina18 [472]

Problem 1 is correct. You use the pythagorean theorem to find the hypotenuse.

==================================================

Problem 2 has the correct answer, but one part of the steps is a bit strange. I agree with the 132 ft/sec portion; however, I'm not sure why you wrote \frac{1 \text{ sec}}{132 \text{ ft}}=\frac{0.59\overline{09}}{78 \text{ ft}}*127 \text{ ft}

I would write it as \frac{1\text{ sec}}{132 \text{ ft}}*127 \text{ ft} = \frac{127}{132} \text{ sec} \approx 0.96 \text{ sec}

==================================================

For problem 3, we first need to convert the runner's speed from mph to feet per second.

17.5 \text{ mph} = \frac{17.5 \text{ mi}}{1 \text{ hr}}*\frac{1 \text{ hr}}{60 \text{ min}}*\frac{1 \text{ min}}{60 \text{ sec}}*\frac{5280 \text{ ft}}{1 \text{ mi}} \approx 25.667 \text{ ft per sec}

Since the runner needs to travel 90-12 = 78 ft, this means\text{time} = \frac{\text{distance}}{\text{speed}} \approx \frac{78 \text{ ft}}{25.667 \text{ ft per sec}} \approx 3.039 \text{ sec}

So the runner needs about 3.039 seconds. In problem 2, you calculated that it takes about 0.96 seconds for the ball to go from home to second base. The runner will not beat the throw. The ball gets where it needs to go well before the runner arrives there too.

-------------

The question is now: how much of a lead does the runner need in order to beat the throw?

Well the runner needs to get to second base in under 0.96 seconds.

Let's calculate the distance based on that, and based on the speed we calculated earlier above.

\text{distance} = \text{rate}*\text{time} \approx (25.667 \text{ ft per sec})*(0.96 \text{ sec}) \approx 24.64032 \text{ ft}

This is the distance the runner can travel if the runner only has 0.96 seconds. So the lead needed is 90-24.64032 = 65.35968 feet

This is probably not reasonable considering it's well over halfway (because 65.35968/90 = 0.726 = 72.6%). If the runner is leading over halfway, then the runner is probably already in the running motion and not being stationary.

As you can see, the runner is very unlikely to steal second base. Though of course such events do happen in real life. What may explain this is the reaction time of the catcher may add on just enough time for the runner to steal second base. For this problem however, we aren't considering the reaction time. Also, not all catchers can throw the ball at 90 mph which is quite fast. According to quick research, the MLB says the average catcher speed is about 81.8 mph. This slower throwing speed may account for why stealing second base isn't literally impossible, although it's still fairly difficult.

5 0
3 years ago
In a chess tournament, each player plays every other player exactly once. If it is known that 105 games were played, how many pl
diamong [38]

Answer:

15 players played in the chess tournament.

Step-by-step explanation:

When there are 15 players, the first player plays 14 games and step aside.

remaining 14 player

next player plays 13 games. steps aside

remaining 13 players

next player plays 12 games. steps aside

remaining 12 players

next player plays 11 games. steps aside

remaining 11 players

.

.

.

.

Last player plays 1 game and steps aside

remaining 1 player who will not play against himself.

∴ Sum of all games played

= 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 105 games played

3 0
3 years ago
a big cruise ship dropped anchor off the Caribbean island of antigua. the heavy anchor dropped into the water at a rate of 2.5 m
AysviL [449]

Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell

                                     (2.5 m/s) x (45 s)  =  112.5 meters .

If it wound up only 40 meters underwater, then it must have fallen

                                      (112.5 m  -  40 m)  =  72.5 meters

from its storage position on the big cruise ship, 
before it ever reached the water.

Since it was falling at the rate of  2.5 m/s, it took

                                     (72.5 m) / (2.5 m/s)  =  29 seconds

to get down to the water surface after it started dropping.

6 0
3 years ago
Can you help me simplify this and explain it -----------------------------------------------------------------------------------
Archy [21]
A. Factor 28 + 7g  7(g <span>+ 4) 

add 
28 </span><span>+ 7g 

= 7 (g </span>+ 4)

B. (12r + 15) – 65 Remove parentheses
12r+15-65

= 12r - 50 

C. 24 – (8p – 12)

24 - (8p - 12) = -8p + 36 

24 - (8p - 12)  -(8p - 12) 8p + 12

= 24-8p+12

Simplify 24-8p+12 

Group like terms
-8p+12+24

Add the numbers  12+24=36

Answer is -8p+36



7 0
3 years ago
Which of the following is the equation of a line perpendicular to the line y = -10x + 1, passing through the point (5,7)?
Viktor [21]
Line 1;
y=-10x+1
Gradient m= -10
Gradient of line 2= 1/10
\frac{y-5}{x-7} = \frac{1}{10}
y-5=\frac{1}{10} {x-7}
y-5=\frac{1}{10} x- \frac{7}{10}
y=\frac{1}{10} x- \frac{43}{10}

6 0
3 years ago
Read 2 more answers
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