5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 <span>The smallest integer in our sequence is 2n = 2*17 = 34</span> Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70
Answer:
Um the picture isn´t very clear it is hard to see it.
Step-by-step explanation:
at least on my end it is.
Answer:
River D: 2780 River C: 2280
Step-by-step explanation:
Please mark brainliest
Answer: The total change is 21.
Since you want to find the change from the lowest to highest, make it into a subtraction problem. First of all, take the smallest number in front of the largest.
20 -1
Next, add a minus sign in between, your equation should look like this:
20 - (-1) = x
Then, you cancel out the negative signs. After that you solve it
20 - (-1) -> 20 + 1.
Lastly, you add them together.
20 + 1 = 21.
In conclusion, the answer is 21.
Answer:
1:500000
Step-by-step explanation:
1 mm (map) equals 500 m (actual) .
Let's convert 500 m to mm.
1m = 1000mm
500m = 500000 mm
So 1mm to 500000mm on a scale is
1:500000
So it's all about converting the metre to million metre then doing the ratio.
In this case we are not to divide anything because it's already in 1.
So it's 1mm on paper then 500000mm on actual.
Thank you
