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nata0808 [166]
3 years ago
14

There are 6 girls and 7 boys in a class. A team of 10 players is to be selected from the class. If the selection is random, what

is the probability of selecting a team of 4 girls and 6 boys?
Mathematics
1 answer:
Luden [163]3 years ago
7 0
For the selection to be 10, there has to be at least 3 girls. So there's a 1/4 chance of 3 girls picked, 1/4 4 girls, 1/4 5 girls and 1/4 6 girls. Because the sum of people has to be 10, if 4 girls are picked, to make 10 people there is a 1/1 chance of 6 boys. 1/4 * 1/1 = 1/4. So 1/4 chance of 4 girls and 6 boys
You might be interested in
approximately 55% of high school students participate in athletic programs. if we choose 5 high school students at random, what
Zigmanuir [339]

Answer:

98.15% probability that at least one of them participate in athletic programs.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they participate in athletic programs, or they do not. The probability of a student participaing in an athletic program is independent of other students, so we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

55% of high school students participate in athletic programs.

This means that p = 0.55

5 high school students

This means that n = 5

What is the probability that at least one of them participate in a athletic program?

Either none participate, or at least one of them does. The sum of the probabilities of these events is 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1).

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.55)^{0}.(0.45)^{5} = 0.0185

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0185 = 0.9815

98.15% probability that at least one of them participate in athletic programs.

6 0
3 years ago
Paula has 3 bananas. She wants to divide each of them into sections. How many 's are there in 3 bananas?
notka56 [123]
1 in each section :)
8 0
3 years ago
Read 2 more answers
What is the slope of a line that contains the points (-1, 9) And 5, 21)
Zigmanuir [339]

<em>It's very simple, all you need is to plug it in the slope formula.</em>

<u>Slope formula:</u>   (y2 - y1) / (x2 - x1)

<em>Then, plug</em>

(9,21) / (-1,5)

Lastly, you solve, which will give you the slope as 0.5.


                       

3 0
4 years ago
Triangle ABC has vertices A(-5, -2), B(7, -5), and C(3, 1). Find the coordinates of the intersection of the three altitudes
fiasKO [112]

Answer:

The coordinates of the intersection of the three altitudes = (-3.5, -1)

Step-by-step explanation:

The altitude of a triangle is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

There are therefore three altitudes possible in a triangle, one from each vertex. All three altitudes always intersect at the same point called the orthocenter of the triangle.

Let the triangle ABC have altitudes AD, BE and CF as shown in the attached image to this solution. Let the orthocentre be O.

The point O is the point where all the coordinates AD, BE and CF meet.

Hence, to obtain the coordinates of O, we just need to equate the equations of two of the lines that serve as the altitude.

Before that, we need to c9mpute the equations of the two altitudes that we will use.

Noting that the altitudes are perpendicular to the sides of the triangle, we can compute the slopes of the altitudes from caldilating the slopes of the sides.

Slope of AB

= (y₂-y₁)/(x₂−x₁)

= (-5 - (-2))/(7 - (-5))

= (-3/12)

= (-1/4)

Slope of its altitude, CF

= -1 ÷ (Slope of AB)

= -1 × (-1/4)

= 4

The equation of CF is given using point C as,

y – y₁ = m(x – x₁)

y - 1 = 4 (x – 3)

y - 1 = 4x - 12

y = 4x + 13

Slope of BC

= (y₂-y₁)/(x₂−x₁)

= (1 - (-5))/(3 - 7)

= (6/-4)

= (-3/2)

Slope of AD

= −1 ÷ (Slope of BC)

= -1 ÷ (-3/2)

= (2/3)

The equation of AD using point A given as,

y – y₁ = m(x – x₁)

y – (-2)) = (2/3) (x – (-5))

y + 2 = (2x/3) + (10/3)

y = (2x/3) + (4/3)

Now equation the equations of the altitudes CF and AD

y = 4x + 13

y = (2x/3) + (4/3)

4x + 13 = (2x/3) + (4/3)

4x - (2x/3) = (4/3) - 13

(10x/3) = (-35/3)

10x = -35

x = -3.5

y = 4x + 13

y = (4×-3.5) + 13 = -14 + 13 = -1

coordinates of the orthocentre of the triangle = (-3.5, -1)

Hope this Helps!!!

6 0
4 years ago
the volume of a cylinder is 24 π cubic feet.what is the volume of a cone having the same base and same height?
dalvyx [7]

\bf \stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}~\hspace{7em}\stackrel{\textit{volume of a cone}}{V=\cfrac{\pi r^2 h}{3}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{volume of a cylinder}}{V=24\pi }~\hspace{7em}\stackrel{\textit{volume of a cone}}{V=\cfrac{24\pi }{3}}\implies V=8\pi


notice the volumes, the cone's volume is really one-third that of the cylinder, assuming "h"eight and "r"adius is the same on both.

7 0
3 years ago
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