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melomori [17]
3 years ago
14

If Carbon Monoxide had a concentration in the air of 0.000518% how many particles out of 331,002,651 would be Carbon Monoxide?

Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0

Answer:

171,459 particles of CO

Step-by-step explanation:

331,002,651×0.000518 = 171459

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When Marcus visited the corner store the first day he bought 3 sodas and 5 bag of chips for a total of $4.05. On the second day
suter [353]

Answer:

a soda cost .65 and chips cost 1.3

Step-by-step explanation:

i hope this helps

7 0
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If 1 is a solution to g (X)=0 what is the other solution
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4 0
3 years ago
Can you guys help me out
marusya05 [52]

Answer:

a. S = 3n + 2

b. There while be 62 squares.

Step-by-step explanation:

We know the first term of this sequence is 5. To figure out the equation, subtract the following term from the previous. Do you see a common difference?

8 - 5 = 3

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We're seeing a constant difference of 3 (which makes this an arithmetic sequence), but the first term is 5. That mean something is being added to make the first term 5. Subtract 3 from 5 to get 2. This means 2 is being added to every multiple of 3, which leads us to the equation: S = 3n + 2.

To find the 20th term of this sequence, substitute n for 20 and do the operations.

S = 3(20) + 2

<em>Multiply 3 by 20, then add 2.</em>

S = 62

The 20th term will have 62 squares.

7 0
3 years ago
Write the product of 7/20 and 3 as a decimal
posledela
7.8
is the answer :) because you have to turn the fraction into a decimal then multiply by 3.

7 0
3 years ago
What is the answer 4b-7-15b+3
Molodets [167]
Simplify

4b−7−15b+3

=4b+−7+−15b+3

Combine Like Terms:

=4b+−7+−15b+3

=(4b+−15b)+(−7+3)

=−11b−4

7 0
3 years ago
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