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Vlad [161]
3 years ago
7

What is the answer 4b-7-15b+3

Mathematics
2 answers:
Molodets [167]3 years ago
7 0
Simplify

4b−7−15b+3

=4b+−7+−15b+3

Combine Like Terms:

=4b+−7+−15b+3

=(4b+−15b)+(−7+3)

=−11b−4

artcher [175]3 years ago
3 0
4b-7-15b+3
-11b-7+3
-11b-4
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Aleks04 [339]
Hi there!

a. 8x^2 - 1
(x^2 - 4x + 5) + (7x^2 + 4x - 6)
= x^2 + 7x^2 - 4x + 4x - 1
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b. 5x^2 + 7x - 7
(7x^2 + 4x - 6) - (2x^2 - 3x + 1)
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Hope this helps!
4 0
3 years ago
Here are 5 cards with a picture of a rose and 3 cards with a picture of a daisy. Alia keeps all the cards down on a table with t
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7 0
3 years ago
In the circle below, DB = 22 cm, and m<DBC = 60°. Find BC. Ignore my handwriting.​
Karo-lina-s [1.5K]

Answer:

BC=11\ cm

Step-by-step explanation:

step 1

Find the measure of the arc DC

we know that

The inscribed angle measures half of the arc comprising

m\angle DBC=\frac{1}{2}[arc\ DC]

substitute the values

60\°=\frac{1}{2}[arc\ DC]

120\°=arc\ DC

arc\ DC=120\°

step 2

Find the measure of arc BC

we know that

arc\ DC+arc\ BC=180\° ----> because the diameter BD divide the circle into two equal parts

120\°+arc\ BC=180\°

arc\ BC=180\°-120\°=60\°

step 3

Find the measure of angle BDC

we know that

The inscribed angle measures half of the arc comprising

m\angle BDC=\frac{1}{2}[arc\ BC]

substitute the values

m\angle BDC=\frac{1}{2}[60\°]

m\angle BDC=30\°

therefore

The triangle DBC is a right triangle ---> 60°-30°-90°

step 4

Find the measure of BC

we know that

In the right triangle DBC

sin(\angle BDC)=BC/BD

BC=(BD)sin(\angle BDC)

substitute the values

BC=(22)sin(30\°)=11\ cm

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3 years ago
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Answer:

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Step-by-step explanation:

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Read 2 more answers
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