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Natali [406]
4 years ago
6

What is the factored form of each expression? 20x + 35y

Mathematics
1 answer:
Tasya [4]4 years ago
5 0
The factored form of 20x+35y would be 5(4x+7y). If you use the distributive property of multiplication, you can see that the expression has not changed. 
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The atomic number of an element B is 17. The number of electrons in its ion B will be:
loris [4]

Answer:

18

Step-by-step explanation:

don't step answer. Because I am lol

8 0
3 years ago
GHJK is a square with diagonals intersecting at L. Given that GH=2 and GL=square root of , complete the statement
Dafna11 [192]

Answer:

GL = square root of 2 = √2

Step-by-step explanation:

Given: GHJK is a square and its diagonals intersect at L

GJ and HK are its two diagonals.

We know that in a square diagonals bisect each other and if length of side is a, then length of its diagonal = √2 a.

Therefore, GJ=HK = √2×2

Since, diagonal intersect at L , L is mid point of GJ and HK

Therefore, GL = √2×2/2 = √2

Hence, GL = square root of 2

4 0
3 years ago
Which of the following shows the correct solution steps and solution to 7x- 4 = -182 7x - 4 = -18 71 - 4+4= -18 + 4 72 = -14 A.
erica [24]

Answer/Step-by-step explanation:

7x- 4 = -182

<em>Step:</em>

Add 4 to both sides

7x - 4 + 4 = -182 + 4

Simplify

7x = -178

Divide both sides by 7

7x/7 = -178/7

Simplify

x = -178/7

Decimal form = -25.4285714286

<u><em>~lenvy~</em></u>

3 0
2 years ago
Read 2 more answers
Solve these linear equations by Cramer's Rules Xj=det Bj / det A:
timurjin [86]

Answer:

(a)x_1=-2,x_2=1

(b)x_1=\frac{3}{4} ,x_2=-\frac{1}{2} ,x_3=\frac{1}{4}

Step-by-step explanation:

(a) For using Cramer's rule you need to find matrix A and the matrix B_j for each variable. The matrix A is formed with the coefficients of the variables in the system. The first step is to accommodate the equations, one under the other, to get A more easily.

2x_1+5x_2=1\\x_1+4x_2=2

\therefore A=\left[\begin{array}{cc}2&5\\1&4\end{array}\right]

To get B_1, replace in the matrix A the 1st column with the results of the equations:

B_1=\left[\begin{array}{cc}1&5\\2&4\end{array}\right]

To get B_2, replace in the matrix A the 2nd column with the results of the equations:

B_2=\left[\begin{array}{cc}2&1\\1&2\end{array}\right]

Apply the rule to solve x_1:

x_1=\frac{det\left(\begin{array}{cc}1&5\\2&4\end{array}\right)}{det\left(\begin{array}{cc}2&5\\1&4\end{array}\right)} =\frac{(1)(4)-(2)(5)}{(2)(4)-(1)(5)} =\frac{4-10}{8-5}=\frac{-6}{3}=-2\\x_1=-2

In the case of B2,  the determinant is going to be zero. Instead of using the rule, substitute the values ​​of the variable x_1 in one of the equations and solve for x_2:

2x_1+5x_2=1\\2(-2)+5x_2=1\\-4+5x_2=1\\5x_2=1+4\\ 5x_2=5\\x_2=1

(b) In this system, follow the same steps,ust remember B_3 is formed by replacing the 3rd column of A with the results of the equations:

2x_1+x_2 =1\\x_1+2x_2+x_3=0\\x_2+2x_3=0

\therefore A=\left[\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right]

B_1=\left[\begin{array}{ccc}1&1&0\\0&2&1\\0&1&2\end{array}\right]

B_2=\left[\begin{array}{ccc}2&1&0\\1&0&1\\0&0&2\end{array}\right]

B_3=\left[\begin{array}{ccc}2&1&1\\1&2&0\\0&1&0\end{array}\right]

x_1=\frac{det\left(\begin{array}{ccc}1&1&0\\0&2&1\\0&1&2\end{array}\right)}{det\left(\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right)} =\frac{1(2)(2)+(0)(1)(0)+(0)(1)(1)-(1)(1)(1)-(0)(1)(2)-(0)(2)(0)}{(2)(2)(2)+(1)(1)(0)+(0)(1)(1)-(2)(1)(1)-(1)(1)(2)-(0)(2)(0)}\\ x_1=\frac{4+0+0-1-0-0}{8+0+0-2-2-0} =\frac{3}{4} \\x_1=\frac{3}{4}

x_2=\frac{det\left(\begin{array}{ccc}2&1&0\\1&0&1\\0&0&2\end{array}\right)}{det\left(\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right)} =\frac{(2)(0)(2)+(1)(0)(0)+(0)(1)(1)-(2)(0)(1)-(1)(1)(2)-(0)(0)(0)}{4} \\x_2=\frac{0+0+0-0-2-0}{4}=\frac{-2}{4}=-\frac{1}{2}\\x_2=-\frac{1}{2}

x_3=\frac{det\left(\begin{array}{ccc}2&1&1\\1&2&0\\0&1&0\end{array}\right)}{det\left(\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right)}=\frac{(2)(2)(0)+(1)(1)(1)+(0)(1)(0)-(2)(1)(0)-(1)(1)(0)-(0)(2)(1)}{4} \\x_3=\frac{0+1+0-0-0-0}{4}=\frac{1}{4}\\x_3=\frac{1}{4}

6 0
4 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!<br> 8−(−3)=
sattari [20]

Answer:

11

Step-by-step explanation:

<em>When you subtract a negative number, you add them.</em>

<em>Example:  5 - (-5) = 5 + 5 = 10</em>

<em>Example:  1 - (-14) = 1 + 14 = 15</em>

<u>Step 1:  Subtract</u>

8 - (-3)

8 + 3

11

Answer:  11

6 0
4 years ago
Read 2 more answers
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