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vlada-n [284]
3 years ago
12

A 20-ounce bag of popcorn costs $2.80. If the unit price stays the same, how much does a 35-ounce bag of popcorn cost?

Mathematics
1 answer:
Wittaler [7]3 years ago
4 0

Answer:

I think the answer is C

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If you roll a fair 10-sided die 7 times, what is the probability that the die lands on "10" exactly 2 times?
nexus9112 [7]

Answer: 2:7 times

Step-by-step explanation: hope it helps u

7 0
2 years ago
-2v3 + v75
Lena [83]

Answer:

a)      3\sqrt{3}

Step-by-step explanation:

Step(i):-

Given     - 2 √3 + √75

     we know that        25 × 3 = 75

                 - 2 √3 + √75    

            =    -2 √3 + \sqrt{25 X 3}

By using

       \sqrt{ab} = \sqrt{a}  \sqrt{b}

          =  -2\sqrt{3} + \sqrt{25} X \sqrt{3}

         =  -2\sqrt{3} + 5  \sqrt{3}

        = (-2 + 5 ) \sqrt{3}

       = 3\sqrt{3}

 

3 0
3 years ago
Which function shown has a greater average rate of change on the invertal calendar [-1,2]
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8 0
3 years ago
My common core lesson 7 3.1
Verizon [17]
What is the question?
5 0
3 years ago
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
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