Dadas as coordenadas dos vértices de uma triângulo ABC, em que A=(1; 1), B=(4; 1)
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Answer:
f(x) = sin(0.62832(x +1))
Step-by-step explanation:
The period of the function is the difference between x=4 and x=-6, which is 10 units. Then the horizontal scaling needs to be such that when x changes by 10, the argument of the sine function changes by 2π. That scaling will make it ...
f(x) = sin(2π(x/10)) = sin(πx/5)
The upward zero-crossing is seen to be at -1, so this function has been shifted left 1 unit. This requires we replace x with x+1:
f(x) = sin(π/5(x +1))
If we use the given numerical value for pi, this becomes ...
f(x) = sin(0.62832(x +1))
