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Arada [10]
3 years ago
6

Please help with this problem!!

Mathematics
1 answer:
hodyreva [135]3 years ago
8 0

The answer is A because the two lines are equal

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Could someone please help me with this? Solution set of lx^2+mx+n=0 is...?
IgorLugansk [536]

Answer:

Simplifying

lx2 + mx + n = 0

Solving

lx2 + mx + n = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1mx' to each side of the equation.

lx2 + mx + -1mx + n = 0 + -1mx

Combine like terms: mx + -1mx = 0

lx2 + 0 + n = 0 + -1mx

lx2 + n = 0 + -1mx

Remove the zero:

lx2 + n = -1mx

Add '-1n' to each side of the equation.

lx2 + n + -1n = -1mx + -1n

Combine like terms: n + -1n = 0

lx2 + 0 = -1mx + -1n

lx2 = -1mx + -1n

Divide each side by 'x2'.

l = -1mx-1 + -1nx-2

Simplifying

l = -1mx-1 + -1nx-2

Step-by-step explanation:

Hope this helped you!

6 0
3 years ago
What is 3 and 3/4 as a decimal
Simora [160]
It should be 3.75 think of it as a dollar 3/4 of a dollar is .75
5 0
3 years ago
Read 2 more answers
Which statements are true?<br>(look at picture)​
Makovka662 [10]

Answer:

D is true, E is true, F is true

Step-by-step explanation:

Hello,

n is an odd number it means that n = 2a+1 where a is integer

A

n^2-1=(2a+1)^2-1=4a^2+4a+1-1=4a(a+1)

this is <u>not</u> an odd number

B

n(n-1)=(2a+1)2a

this is <u>not</u> an odd number

C

(n-1)^2=(2a+1-1)^2=4a^2

this is <u>not</u> an odd number

D

n^2+2=(2a+1)^2+2=4a^2+4a+1+2=4a^2+4a+3= 2(2a^2+2a+1)+1

so this is an odd number

E

n(n-2)=(2a+1)(2a-1)=4a^2-1=4a^2-2+1=2(2a^2-1)+1

so this is an odd number

F

(n-2)^2=(2a+1-2)^2=(2a-1)^2=4a^2-4a+1 = 2(2a^2-2a)+1

this is an odd number

hope this helps

7 0
3 years ago
Simplify 4x-3(x-2). I'm stuck xD
alexira [117]

Answer:

Simplified = x + 6

4 0
2 years ago
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-.3 0.5 .55 -.35 least to greatest
aliina [53]
I believe the correct order is -.35, -.3, 0.5, .55
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