Answer:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
- d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
- After first dose residual drug amount is:
d= 500*0.045= 22.5 mg
- After second dose:
d= 22.5*2= 45 mg
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Answer:
x = 16
Step-by-step explanation:
Solve for x by simplifying both sides of the equation, then isolating the variable.
<h2>(x, y) = (x, 2 + 5/6 x)</h2>
Step-by-step explanation:
-5x + 6y = 12
y = 5/6x + 2
<h2>_______________</h2>
-5x + 6y = 12
-5x + 6(5/6x + 2) = 12
-5x + 5x + 12 = 12
x real numbers
(x, y) = (x, 2 + 5/6 x)
Answer: 7
Step-by-step explanation: The only pattern in this sequence that I can see is addition by 4. Therefore, the 3rd term is 15, the 2nd is 11, the 1st is 7.
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Answer:
X^2-11x+28
Step-by-step explanation:
