Answer:
The general plan is to find BM and from that CM. You need 2 equations to do that.
Step One
Set up the two equations.
(7 - BM)^2 + CM^2 = (4*sqrt(2) ) ^ 2 = 32
BM^2 + CM^2 = 5^2 = 25
Step Two
Subtract the two equations.
(7 - BM)^2 + CM^2 = 32
BM^2 + CM^2 = 25
(7 - BM)^2 - BM^2 = 7 (3)
Step three
Expand the left side of the new equation labeled (3)
49 - 14BM + BM^2 - BM^2 = 7
Step 4
Simplify And Solve
49 - 14BM = 7 Subtract 49 from both sides.
-49 - 14BM = 7 - 49
- 14BM = - 42 Divide by - 14
BM = -42 / - 14
BM = 3
Step Five
Find CM
CM^2 + BM^2 = 5^2
CM^2 + 3^2 = 5^2 Subtract 3^2 from both sides.
CM^2 = 25 - 9
CM^2 = 16 Take the square root of both sides.
sqrt(CM^2) = sqrt(16)
CM = 4 < Answer
Step-by-step explanation:
The standard form of a quadratic equation is ,
ax² + bx + c = 0.
And the formula to find the discriminant is b² - 4ac.
Here the first step is to change the given equation into standard form. So, add 1 to each sides of the equation. Therefore,
2x² – 9x + 2+1 = –1 + 1
2x² – 9x + 3 = 0
Next step is to compare the given equation with this equation to get the value of a, b and c.
After comparing the equations we will get a = 2, b = -9 and c = 3.
So, discriminant = b²- 4ac
=( -9)²-4 (2)(3)
= 81 - 24
= 57
So, discriminant of the given equation is 57.
57 is greater than 0 and square root of 57 will result real number.
So, the correct choice is C: The discriminant is greater than 0, so there are two real roots.
Answer:
it translates to something i can't say on here ;)
Answer:
y = -2x - 10
Step-by-step explanation:
Slope intercept form of equation is of form
y = mx+c
where m is the slope of line and c is the y intercept of the line.
Y intercept is point on y axis where the line intersects the y axis.
_____________________________
Given equation
y = -2x +4
comparing it with y = mx+ c
m = -2 , c = 4
_____________________________
when two lines are parallel, their slopes are equal.
Let the equation of new line in slope intercept form be y = mx + c
Thus slope of of new required line is -2
Thus m for new line is -2.
now, equation of required line : y = -2x+c
Given that this line passes through (-4, -2). This point shall should satisfy equation y = -2x+c.
Substituting the value of (-4, -2) we have
-2 = -2(-4)+c
=> -2 = 8 +c
=> -2 -8 = c
=> c = -10.
Thus , equation of required line is y = -2x - 10.
