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dolphi86 [110]
3 years ago
8

If a wiggling string has a natural frequency of 34.5 Hz to produce 4 harmonics, what is the period of the string?

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0

Answer:

T = \frac{1}{f}

And replacing we got:

T = \frac{1}{34.5 Hz}= 0.0290 s

And then we can conclude that with the conditions given the period of the string would be 0.0290 s

Step-by-step explanation:

For this case we know the frequency associated to the 4 harmonic.

We know that by definition the frequency is the inverse of the period:

f= \frac{1}{T}

If we solve for the period we got:

T = \frac{1}{f}

And replacing we got:

T = \frac{1}{34.5 Hz}= 0.0290 s

And then we can conclude that with the conditions given the period of the string would be 0.0290 s

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Answer:

a) correct option is

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Step-by-step explanation:

Given data:

mean number is given as 6.2

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

we know that variance is given as\sigma^2 = mean = 6.2

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correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2  surgeries  in a given day is

P(X \leq 2) = P(X =0) + P(X =1) + P(X =2)

                 = \frac{e^{-6.2} 6.2^0}{0!} +\frac{e^{-6.2} 6.2^1}{1!} +\frac{e^{-6.2} 6.2^2}{2!}

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                 = 0.053617

                = 0.0536

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2 years ago
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2 years ago
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andre [41]

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2 years ago
singh works at a restaurant where he is paid by the hour plus time and a half for his hours over 40. last week he worked four ho
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$8.5 per hour

Step-by-step explanation:

Number of overtime hours = 4 hours

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2 years ago
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