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Nuetrik [128]
3 years ago
6

HELP I NEED HELP ASAP

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

The answer is D

{x}^{2}  + 6x + 9 = 0 \\ x =  - 3

That's the only equation will get us one point

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Watch help Video
Alexus [3.1K]

Answer: 5y − 1 + y^{2}

Step-by-step explanation:

Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below. Thank you!

<u>Step 1:</u><u> </u><u><em>Collect like terms.</em></u>

(3y + 2y) + (6 − 3 − 4) + (-6y^{2} + 7y^{2})

<u>Step 2: </u><u><em>Simplify.</em></u>

5y − 1 + y^{2}

~I hope I helped you! :) Good luck!~

6 0
4 years ago
In which number does the 6 have a value that is 10 times greater than its value in 65?
Juliette [100K]

Answer:

D

Step-by-step explanation:

6*10 = 60 so which answer choice has a 60 in and that will be D.

8 0
3 years ago
Can someone help me?
SOVA2 [1]

Answer:

what does the picture say?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
state the domain, the range, and the intervals on which function is increasing, decreasing, or constant in interval notation
erma4kov [3.2K]

Answer:

  • domain (-∞, ∞)
  • range (-∞, 4]
  • increasing (-∞, 0)
  • decreasing (0, ∞)
  • constant (only at x=0, not on any interval)

Step-by-step explanation:

The graph is of the equation y = -x^2 +4. It is a polynomial of even degree, so has a domain of all real numbers: (-∞, ∞).

The vertical extent of the graph includes y=4 and all numbers less than that:

  range: (-∞, 4]

The graph is increasing to the left of its vertex at x=0, decreasing to the right.

  increasing (-∞, 0); decreasing (0, ∞)

There is no interval on which the function is constant. It has a horizontal tangent at x=0, but a single point does not constitute an interval.

8 0
3 years ago
Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75.percent f
irinina [24]

Answer:

33%

Step-by-step explanation:

Assuming the weight of the mixture to be 100g**, then the weight of ryegrass in the mixture would be 30g.

Also, assume the weight mixture X used in the mixture is Xg, then the weight of mixture Y used in the mixture would be (100-X)g.

So we can now equate the parts of the ryegrass in the mixture as:

0.4X + 0.25(100-X) = 30

<=> 0.4X + 25 - 0.25X = 30

<=> 0.15X = 5

<=> X = 5/0.15 = 500/15 = 100/3

So the weight of mixture X as a percentage of the weight of the mixture

= (weight of X/weight of mixture) * 100%

= (100/3)/100 * 100%

= 33%

3 0
4 years ago
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