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3 years ago

6

Using the numbers 4.3, -1.07, and -2.917, write an expression containing both addition and subtraction that simplifies to a nega

tive number.

1 answer:

Advocard [28]3 years ago

6 0

Answer:

-1.07+(-2.917)-4.3=-8.287

Step-by-step explanation:

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A^2-b^2 a^2b-ab^2<br>-------------- ÷ ---------------a^2b+ab^2 a^2b- ab^2

Damm [24]

Answer:

$\huge{= \frac{ {a}^{2} - {b}^{2} }{ {a}^{2b} + {ab}^{2} }}$

Step-by-step explanation:

$\huge{ \frac{ {a}^{2} - {b}^{2} }{ {a}^{2b} + {ab}^{2} } \div \frac{ {a}^{2b} - {ab}^{2} }{ {a}^{2b} - {ab}^{2} }}$

$\huge{\frac{ {x}^{2} - {b}^{2} }{ {a}^{2b} + {ab}^{2} } \div 1}$

$\huge{\boxed{\green{= \frac{ {a}^{2} - {b}^{2} }{ {a}^{2b} + {ab}^{2} }}}}$

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3 years ago

Calculate the resistance of a 270-cm length of copper wire with a 0.030-cm2 cross-sectional area. ( = 1.8 · 10-6 ohm-cm) R = ___

devlian [24]

Answer:

Given:-

The length of copper wire (L) = 270 cm

Area of cross-sectional (A) = 0.030 $cm^2$

and specific resistance (ρ) = $1.8 \times 10^{-6}$ ohm-cm.

Use the formula R=(Specific resistance*L)/A, to calculate the Resistance(R)

then, $R=\frac{1.8 \times 10^{-6} \times 270}{0.030}$ ohm

Simplify:

R = 0.0162 ohm = $1.62\times 10^{-2}$ ohm

Therefore, the resistance of copper wire is, $1.62\times 10^{-2}$ Ω

8 0

3 years ago

Please answer :) Easy question

lutik1710 [3]

4. ^

5. A slope is a line nevertheless and it keeps changing, while the rise over run is also a slope. This means that the only correct answer can be a 2 dimensional figure.

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3 years ago

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Name the intersection of planes DCG and EFG

cupoosta [38]

<span>GH would be the intersection in this case. This is the place where the planes come together. An intersection is where two things come together. This enables an object to create a shape like a box and gives support to the sides that mesh.</span>

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3 years ago

Evaluate f(0)<br> f(x) = - 4x + 9

german

F(0)= -4(0)+9
F(0)= 0+9
F(0)=9

4 0

2 years ago