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Gennadij [26K]
3 years ago
6

Using the numbers 4.3, -1.07, and -2.917, write an expression containing both addition and subtraction that simplifies to a nega

tive number.
Mathematics
1 answer:
Advocard [28]3 years ago
6 0

Answer:

-1.07+(-2.917)-4.3=-8.287

Step-by-step explanation:

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A^2-b^2 a^2b-ab^2<br>-------------- ÷ ---------------a^2b+ab^2 a^2b- ab^2​
Damm [24]

Answer:

\huge{=  \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }}

Step-by-step explanation:

\huge{ \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b}  +  {ab}^{2}  }  \div  \frac{ {a}^{2b} -  {ab}^{2}  }{ {a}^{2b} -  {ab}^{2}  }}

\huge{\frac{ {x}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }  \div 1}

\huge{\boxed{\green{=  \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }}}}

5 0
3 years ago
Calculate the resistance of a 270-cm length of copper wire with a 0.030-cm2 cross-sectional area. ( = 1.8 · 10-6 ohm-cm) R = ___
devlian [24]

Answer:

Given:-

The length of copper wire (L) = 270 cm

Area of cross-sectional (A) = 0.030 cm^2

and specific resistance (ρ) = 1.8 \times 10^{-6} ohm-cm.

Use the formula  R=(Specific resistance*L)/A, to calculate the Resistance(R)

then, R=\frac{1.8 \times 10^{-6} \times 270}{0.030} ohm

Simplify:

R = 0.0162 ohm = 1.62\times 10^{-2} ohm

Therefore, the resistance of copper wire is,  1.62\times 10^{-2} Ω


8 0
3 years ago
Please answer :) Easy question
lutik1710 [3]
4. ^

5. A slope is a line nevertheless and it keeps changing, while the rise over run is also a slope. This means that the only correct answer can be a 2 dimensional figure.

7 0
3 years ago
Read 2 more answers
Name the intersection of planes DCG and EFG
cupoosta [38]
<span>GH would be the intersection in this case. This is the place where the planes come together. An intersection is where two things come together. This enables an object to create a shape like a box and gives support to the sides that mesh.</span>
7 0
3 years ago
Evaluate f(0)<br> f(x) = - 4x + 9
german
F(0)= -4(0)+9
F(0)= 0+9
F(0)=9
4 0
2 years ago
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