Answer:
The range of the 95% data (X) = 238.3 days < X < 289.9 days
Step-by-step explanation:
Given;
mean of the normal distribution, m = 264.1 days
standard deviation, d = 12.9 days
between two standard deviation below and above the mean is 96% of all the data.
two standard deviation below the mean = m - 2d
= 264.1 - 2(12.9)
= 238.3 days
two standard deviation above the mean = m + 2d
= 264.1 + 2(12.9)
= 289.9 days
The middle of the 95% of most pregnancies would be found in the following range;
238.3 days < X < 289.9 days
Y=-2x-3 thats the final answer
for a normal triangle its (bh)/2 but this is a right triangle so you multiply the two perpendicular sides and divide it by 2
32(40-4)
32*40 - 32*4
1,280 - 128=
1,152
therefor
32*36= 1,152
