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3 years ago

Order of operations what should be done first to evaluate 6+ (-5-7) ÷ 2 -8(3)

Mathematics

1 answer:

Maru [420]3 years ago

3 0

Answer:-24

Step-by-step explanation:

6+(-5-7) ➗ 2-8(3)

6-12 ➗ 2-24

6-6-24

0-24=-24

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Which set of numbers can represent the side lengths, in inches, of an acute triangle?

MrMuchimi

Answer:

B. 5, 7, 8

Step-by-step explanation:

When you take the sum of the squares of 5 and 7 they are greater than the square of 8.

5² + 7² = 8² Simplify

25 + 49 = 64 Add

74 > 64

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3 years ago

-4x - 8 = -(5x + 3) pleasee

Korvikt [17]

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2 years ago

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No Solutions:<br> 2x+9+3x+x=????

kotegsom [21]

2x+3x+x+9 = ??
5x+x+9 = ??
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6x = -9 ---- subtract 9 on both sides

x = - 3/2 ----- didvide by 6 on both sides, simplify

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2 years ago

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The ________________ measures the spread of the middle 50% of the data set.

Scilla [17]

Answer:

C. interquartile range

Step-by-step explanation:

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"The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest."

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6 0

2 years ago

P (6,6) y=2/3x

matrenka [14]

Answer:

$y = -\frac{3}{2}x+15$

Step-by-step explanation:

Given:

Given point P(6, 6)

The equation of the line.

$y = \frac{2}{3}x$

We need to find the equation of the line perpendicular to the given line that contains P

Solution:

The equation of the line.

$y = \frac{2}{3}x$

Now, we compare the given equation by standard form $y = mx +c$

So, slope of the line $m_{1} = \frac{2}{3}$ , and

y-intercept $c=0$

We know that the slope of the perpendicular line $m_{1}\times m_{2} = -1$

$m_{2}=-\frac{1}{m_{1}}$

$m_{2}=-\frac{1}{\frac{2}{3} }$

$m_{2}=-\frac{3}{2}$

So, the slope of the perpendicular line $m_{2}=-\frac{3}{2}$

From the above statement, line passes through the point P(6, 6).

Using slope intercept formula to know y-intercept.

$y=mx+c$

Substitute point $P(x_{1}, y_{1})=P(6, 6)$ and $m = m_{2}=-\frac{3}{2}$

$6=-\frac{3}{2}\times 6 +c$

$6=-3\times 3 +c$

$c=6+9$

$c=15$

So, the y-intercept of the perpendicular line $c=15$

Using point slope formula.

$y=mx+c$

Substitute $m = m_{2}=-\frac{3}{2}$ and $c=15$ in above equation.

$y = -\frac{3}{2}x+15$

Therefore: the equation of the perpendicular line $y = -\frac{3}{2}x+15$

8 0

3 years ago