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Furkat [3]
4 years ago
11

A bag contains 7 red marbles, 4 white marbles, and 11 blue marbles. Find P ( not red).

Mathematics
1 answer:
barxatty [35]4 years ago
6 0
If it's multiplied it is 44. If it is added, it is 15. If it is divided, it would be 4/11 or 11/4.
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Azarai is looking to purchase a new pair of basketball shorts costing $40. The New Jersey state tax rate is 7.5 percent. What fi
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Answer:

$43.00

Step-by-step explanation:

final price = marked price + tax

= marked price + (tax rate) · (marked price)

= (marked pric) · (1 + tax rate)

= $40.00 · 1.075

= $43.00

7 0
3 years ago
Please answer correctly
ivanzaharov [21]

Answer:

Answer is B=280

Step-by-step explanation:

6)/7=>>}{÷\¦^~<]||]>^¬)56)7899)/,))-557:

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3 years ago
A price of a gallon of milk is increasing at a rate of 2% each year if a gallon of milk cost $3.75 in 2017 how much will a gallo
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Answer:3.81

Step-by-step explanation:

because you add  2% each year

8 0
3 years ago
Based on the data set shown, which of the following is a true statement?
Ilya [14]
Mean: 1
Mode; 1
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Your answer is A.

7 0
3 years ago
Read 2 more answers
The brand manager for a brand of toothpaste must plan a campaign designed to increase brand recognition. He wants to first deter
JulsSmile [24]

Answer:

1) n=114

2) n=59

3) On this case no, because if we survey just the adults of the nearest college that would be a convenience sample. And when we use "convenience sample" we have some problems associated to bias. This methodology it's not appropiate in order to have a good estimation of the parameter of interest. It's better use a random, cluster or stratified sampling.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 80% of confidence, our significance level would be given by \alpha=1-0.80=0.2 and \alpha/2 =0.1. And the critical value would be given by:

z_{\alpha/2}=-1.28, z_{1-\alpha/2}=1.28

Part 1

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.06 or 6% points, and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Since we don't have a prior estimate of \het p we can use 0.5 as a good estimate, replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.06}{1.28})^2}=113.77  

And rounded up we have that n=114

Part 2

On this case we have a prior estimate for the population proportion and is \hat p =0.85 so replacing the values into equation (b) we got:

n=\frac{0.85(1-0.85)}{(\frac{0.06}{1.28})^2}=58.027

And rounded up we have that n=59

Part 3

On this case no, because if we survey just the adults of the nearest college that would be a convenience sample. And when we use "convenience sample" we have some problems associated to bias. This methodology it's not appropiate in order to have a good estimation of the parameter of interest. It's better use a random, cluster or stratified sampling.

5 0
3 years ago
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