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gizmo_the_mogwai [7]
3 years ago
12

A plane leaves at 11:22 am .and arrived at 3:13 pm. how long was the flight?

Mathematics
1 answer:
ale4655 [162]3 years ago
7 0

Answer:

3 hours and 51 minutes

Step-by-step explanation:

Take the ending time and subtract the start time

3:13pm - 11:22am

Remember that pm means aft 12 o'clock in the after noon so add 12 hours

12+3:13 - 11:22

15:13 - 11:22

We are subtracting more minutes than we have so we have to borrow from the hours

1 hour = 60 minutes

14 : 60+13 - 11:22

14:73 - 11:22

3: 51

3 hours and 51 minutes

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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
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Answer:

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Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

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2.

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2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

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