Answer:
And the best option would be:
c. 1450 +/- 12
Step-by-step explanation:
Information provided
represent the sample mean for the SAT scores
population mean (variable of interest)
represent the sample variance given
n=25 represent the sample size
Solution
The confidence interval for the true mean is given by :
(1)
The sample deviation would be
The degrees of freedom are given by:
The Confidence is 0.954 or 95.4%, the value of
and
, assuming that we can use the normal distribution in order to find the quantile the critical value would be
The confidence interval would be
And the best option would be:
c. 1450 +/- 12
Answer:
70
Step-by-step explanation:
Evaluate 3 b^2 - b where b = 5:
3 b^2 - b = 3×5^2 - 5
Hint: | Evaluate 5^2.
5^2 = 25:
3×25 - 5
Hint: | Multiply 3 and 25 together.
3×25 = 75:
75 - 5
Hint: | Subtract 5 from 75.
| 7 | 5
- | | 5
| 7 | 0:
Answer: 70
Answer: C. (2, -4)
Step-by-step explanation:
Take into consideration that y is less than or equal to -2. The only option in which the y value is less than or equal to -2 is option C., thus C would correctly solve the system of inequalities.