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Elis [28]
3 years ago
7

According to​ Bayes' Theorem, the probability of event​ A, given that event B has​ occurred, is as follows.

Mathematics
1 answer:
zubka84 [21]3 years ago
8 0

Answer:

0.0625

Step-by-step explanation:

<u>Data</u>

  • P(A) = 1/4
  • P(A') = 3/4
  • P(B|A)= 1/10
  • P(B|A') = 1/2

The probability of event​ A, given that event B has​ occurred is computed with the following equation:

P(A|B) = [P(A)*P(B|A)]/[P(A)*P(B|A)+P(A')*P(B|A')]

Replacing with data:

P(A|B) = [1/4*1/10]/[1/4*1/10+3/4*1/2] = 0.0625

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lesya [120]

Answer:

B

Step-by-step explanation:

=3+(-7)

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Hope this will help ya!

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3 years ago
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Factor: 3x^2 - 288y^2 - 36
erica [24]

Answer:

3x^2-288y^2-36

Rewrite -36 as 12×3

Rewrite -288 as 96×3

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40 points plz help if u can Which function has no Zeroes? Select all that apply.
Damm [24]
<h3>2 Answers: Choice C and choice D</h3>

y = csc(x) and y = sec(x)

==========================================================

Explanation:

The term "zeroes" in this case is the same as "roots" and "x intercepts". Any root is of the form (k, 0), where k is some real number. A root always occurs when y = 0.

Use GeoGebra, Desmos, or any graphing tool you prefer. If you graphed y = cos(x), you'll see that the curve crosses the x axis infinitely many times. Therefore, it has infinitely many roots. We can cross choice A off the list.

The same applies to...

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So we can rule out choices B, E and F.

Only choice C and D have graphs that do not have any x intercepts at all.

------------

If you're curious why csc doesn't have any roots, consider the fact that

csc(x) = 1/sin(x)

and ask yourself "when is that fraction equal to zero?". The answer is "never" because the numerator is always 1, and the denominator cannot be zero. If the denominator were zero, then we'd have a division by zero error. So that's why csc(x) can't ever be zero. The same applies to sec(x) as well.

sec(x) = 1/cos(x)

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Vladimir [108]
Yes, Dean is correct.

13% = 13/100 = 0.13

0.1 = 0.10

0.13 is greater than 0.10.
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3 years ago
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