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Murrr4er [49]
3 years ago
15

Народ творець української пісні

Engineering
1 answer:
muminat3 years ago
3 0

Answer:  Що таке пісня Еврекан?

Explanation: Я ніколи не чув про це...

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These waveforms are applied to a gated D latch, which is initially RESET. Which of the areas identified on the Q waveform is inc
Andrej [43]

Question Completion with Options:

A) Area a B) Area b C) Area c D) Area d

Answer:

The incorrect waveform identified on the Q waveform is the:

C) Area c.

Explanation:

Area c is the incorrect waveform because its output is not correct.  The Q waveform indicates that the electrical forces project toward the negative pole of the lead axis.  A gated D latch is a flip flop latch with an additional control input, which determines when to change the state of the circuit. Most times, this control unit is a clock input or an enable input.

8 0
3 years ago
Coulomb's Law Two point charges experience an attractive force of 10.8 N when they are separated by 2.4 m. VWhat force in newton
SashulF [63]

Answer:

The force between the charges when the separation decreases to 0.7 meters equals 126.955 Newtons

Explanation:

We know that for two point charges of magnitude q_{1},q_{2} the magnitude of force between them is given by

F=\frac{k_{e}q_{1}\cdot q_{2}}{r^{2}}

where

k_{e} is constant

r is the separation between the charges

Initially when the charges are separated by 2.4 meters the force can be calculated as

F_{1}=\frac{k_{e}\cdot q_{1}q_{2}}{2.4^{2}}\\\\10.8=\frac{k_{e}\cdot q_{1}q_{2}}{2.4^{2}}\\\\\therefore k_{e}\cdot q_{1}q_{2}=10.8\times 2.4^{2}=62.208

Now when the separation is reduced to 0.7 meters the force is similarly calculated as

F_{2}=\frac{k_{e}\cdot q_{1}q_{2}}{0.7^{2}}

Applying value of the constant we get

F_{1}=\frac{62.208}{0.7^{2}}

Thus F_{2}=126.955Newtons

5 0
3 years ago
What gives thrill in a roller coaster? High speed or Changing acceleration? Explain your answer.
iris [78.8K]

Answer:

They both work together in order to create a good experience for the passenger, but I think that the answer is changing acceleration because when  the rollercoaster changes acceleration it gives it speed.

Explanation:

I really hope this helps.

8 0
3 years ago
Calculate KI for a rectangular bar containing an edge crack loaded in three-point bending where P=35.0 kN, W=50.8 mm, B=25 mm, a
Katyanochek1 [597]

Answer:

K_{I}=5.21 MPa\sqrt{m}

Explanation:

given data

Load P = 35 kN

Width of bar W = 50.8 mm

Breadth of bar B = 25 mm

Ratio of crack length to width α = a/W = 0.2

solution

we get here KI for a rectangular bar that is express as

K_{I} = \frac{6P}{BW}Y\sqrt{\pi a}   ................................1

here Y is the geometrical function

so

Y = \frac{1.12+\alpha (3.43\alpha -1.89)}{1-0.55\alpha}

Y = \frac{1.12+0.2(3.43\times 0.2-1.89)}{1-0.55\times 0.2}  

Y = \frac{0.8792}{0.89}  

Y = 0.9878

so put here value in equation 1

K_{I} = \frac{6\times 35\times 10^{3}}{0.025\times 0.0508}\times 0.9878\times \sqrt{3.1415\times (0.2\times 0.0508)}    

K_{I} = 165354.33\times 10^{3}\times 0.9878\times 0.0319

K_{I} = 5210.45 × 10³  Pa\sqrt{m}  

K_{I} = 5.21 MPa \sqrt{m}

5 0
3 years ago
You are evaluating a variety of new materials for use in the femoral stem of a hip joint replacement.
Lisa [10]

Answer:

a

Explanation:

5 0
3 years ago
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