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Murrr4er [49]
3 years ago
15

Народ творець української пісні

Engineering
1 answer:
muminat3 years ago
3 0

Answer:  Що таке пісня Еврекан?

Explanation: Я ніколи не чув про це...

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What is the weight of a glider with a mass of 4.9 grams?
timama [110]

Answer:

0.0481 N

Explanation:

The mass of a body is the quantity of matter stored in that body. It is a property that measures resistance to acceleration when a force is applied. The S.I unit of mass is the kilogram (kg).

The weight of a body is the force exerted on that body by gravity. The S.I unit of weight is the Newton (N). The weight of an object can also be defined as the force acting on the object. The formula for weight is:

Weight (W) = Mass (m) × acceleration due to gravity(g).

Giving that: mass (m) = 4.9 g = 0.0049 g and acceleration due to gravity (g) = 9.81 m/s².

Therefore, Weight (W) = 0.0049 × 9.81 = 0.0481 N

4 0
3 years ago
A reversible compression of 1 mol of an ideal gas in a piston/cylinder device results in a pressure increase from 1 bar to P2 an
Mashutka [201]

Answer:

attached below

Explanation:

6 0
3 years ago
Select the correct statement(s) regarding frequency modulation (FM). a. baseband amplitude changes (information) are captured as
mario62 [17]
<h3>All of the above statement are correct statement.</h3>

<u>Explanation</u>

  • Base-Band amplitude changes are captured as carrier wave wave frequency changes. In order to convert signal amplitude changes to changes in frequency, we need a device like VCO.
  • The bandwidth in the frequency domain increases with the change in carrier frequency.

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3 years ago
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3 years ago
A brittle material is subjected to a tensile stress of 1.65 MPa. If the specific surface energy and modulus of elasticity for th
8090 [49]

Answer:

The maximum length of a surface flaw that is possible without fracture is

2.806 \times 10^{-4} m

Explanation:

The given values are,

σ=1.65 MPa

γs=0.60 J/m2

E= 2.0 GPa

The maximum possible length is calculated as:

\begin{gathered}a=\frac{2 E \gamma_{s}}{\pi \sigma^{2}}=\frac{(2)\left(2 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}\right)(0.60 \mathrm{~N} / \mathrm{m})}{\pi\left(1.65\times 10^{6} \mathrm{~N} / \mathrm{m}^{2}\right)^{2}} \\=2.806 \times 10^{-4} \mathrm{~m}\end{gathered}

The maximum length of a surface flaw that is possible without fracture is

2.806 \times 10^{-4} m

7 0
3 years ago
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