Explanation:
Hello,
Here i am using vectors
\vec{AB}=\vec{DC}=3\vec{i}+3\vec{j}AB=DC=3i+3j
==> AB//DC and AD//BC (definition of a translation)
The quadrilater ABCD is a parallelogram:
so
1) his diagonals have the same length;
2) his diagonals are cutting in the middle.
(these are proprieties of a parallelogram)
Answer: c. The Professional Engineers Act and Board Rules
Explanation:
The reference source may be consulted to answer questions regarding the Professional Engineers Act is the The Professional Engineers Act and Board Rules.
The Professional Engineers Act and Board Rules is an Act that was established in order to regulate the qualifications for professional engineered, register them and also make sure that their conducts and behavior are looked into.
Answer:
metals, composite, ceramics and polymers.
Explanation:
The four categories of engineering materials used in manufacturing are metals, composite, ceramics and polymers.
i) Metals: Metals are solids made up of atoms held by matrix of electrons. They are good conductors of heat and electricity, ductile and strong.
ii) Composite: This is a combination of two or more materials. They have high strength to weight ratio, stiff, low conductivity. E.g are wood, concrete.
iii) Ceramics: They are inorganic, non-metallic crystalline compounds with high hardness and strength as well as poor conductors of electricity and heat.
iv) Polymers: They have low weight and are poor conductors of electricity and heat
Answer: downward velocity = 6.9×10^-4 cm/s
Explanation: Given that the
Diameter of the smoke = 0.05 mm = 0.05/1000 m = 5 × 10^-5 m
Where radius r = 2.5 × 10^-5 m
Density = 1200 kg/m^3
Area of a sphere = 4πr^2
A = 4 × π× (2.5 × 10^-5)^2
A = 7.8 × 10^-9 m^2
Volume V = 4/3πr^3
V = 4/3 × π × (2.5 × 10^-5)^3
V = 6.5 × 10^-14 m^3
Since density = mass/ volume
Make mass the subject of formula
Mass = density × volume
Mass = 1200 × 6.5 × 10^-14
Mass M = 7.9 × 10^-11 kg
Using the formula
V = sqrt( 2Mg/ pCA)
Where
g = 9.81 m/s^2
M = mass = 7.9 × 10^-11 kg
p = density = 1200 kg/m3
C = drag coefficient = 24
A = area = 7.8 × 10^-9m^2
V = terminal velocity
Substitute all the parameters into the formula
V = sqrt[( 2 × 7.9×10^-11 × 9.8)/(1200 × 24 × 7.8×10^-9)]
V = sqrt[ 1.54 × 10^-9/2.25×10-4]
V = 6.9×10^-6 m/s
V = 6.9 × 10^-4 cm/s
Answer:
<h2>destabilizing load:</h2>
The common definition of a destabilising load is if the load is free to move with the flange, it's a destabilising load. The stress due to the lateral bending of the flange is increased, which means the beam is closer to buckling than it would be without the additional moment.
<h2>normal load:</h2>
Something that is normal is usual and ordinary, and is what people expect.The leakage crack is a postulated crack that, under normal operating loads (pressure, weight, thermal expansion), will discharge a detectable amount of fluid.
The leak rates are calculated based on the flaw geometry, the applied loads, and the crack morphology. The crack opening displacement and crack morphology are typically based on two cases: (1) a fatigue-induced transgranular crack and (2) a corrosion-induced intergranular crack. The leak flow through a crack must be analyzed with the correct thermohydraulic model that captures, as the fluid progresses from the inner diameter (ID) to the outer diameter (OD), a subcooled phase (pressurized hot water) at the ID entrance into the crack, a steam formation phase somewhere between the ID and the OD, and then a two-phase flow region toward the OD, and discharge into the containment environment.