Answer:
sum2 = 0
counter = 0
lst = [65, 78, 21, 33]
while counter < len(lst):
sum2 = sum2 + lst[counter]
counter += 1
Explanation:
The counter variable is initialized to control the while loop and access the numbers in <em>lst</em>
While there are numbers in the <em>lst</em>, loop through <em>lst</em>
Add the numbers in <em>lst</em> to the sum2
Increment <em>counter</em> by 1 after each iteration
Answer: Instrumentality;low
Explanation: Instrumentality is the impact a person have or will be able to render to a given activity or his or her job. The Instrumentality of a person has been found to be proportional to the what outcome of the person's efforts. Especially if the person's explanations are meant.
When a person's expectations are not meant it will cause the person's Instrumentality to be low.
Answer:
Tension can be easily explained in the case of bodies hung from chain, cable, string
Explanation
uniform speed, tension; T = W.
T=m(g±a)
The circuit that may not be used to determine the value of the resistor is (Option A). See the attached image.
<h3>
What is a resistor?</h3>
A resistor is a component of an electronic circuit that restricts or regulates the passage of electrical current.
Resistors can also be used to supply a fixed voltage to an active device such as a transistor.
<h3>What is the purpose of a resistor?</h3>
A resistor is a two-terminal electrical component that offers resistance to current flow. Resistors are commonly employed in electrical circuits to reduce current flow, split voltages, impede transmission signals, and bias active parts.
<h3>
What is a circuit?</h3>
Individual electronic components such as resistors, transistors, capacitors, inductors, and diodes are linked by electrical wires or traces through which electric current can pass to form an electronic circuit.
Learn more about circuits:
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Answer:
A). Dry unit weight = 1657.08Kg/m3
B). Porosity = 0.37
C). Void ratio = 0.593
D). 0.712
Explanation:
Total unit weight, Y = 120pcf =1922.2 Kg/m3
Specific gravity of solids, Gs = 2.64
Water content, w = 16%
A). Dry unit weight
Yd = Y/(1+w)
= 1922.2/(1+0.16) = 1657.08Kg/m3
B). Porosity
However void ratio, e = Gs×Yw/Yd, where Yw = 1000Kg/m3
Void ratio = 2.64×1000/1657.08 = 0.593
And porosity = e/(1+e) =0.593/(1+0.593) = 0.37
C). void ratio, e = 0.593
D). Degree of saturation, S = m×Gs/e where m =water content
S = 0.16×2.64/0.593 = 0.712