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3 years ago

The solid was created by connecting two congruent square pyramids to a rectangular prism.

Mathematics

2 answers:

svlad2 [7]3 years ago

8 0

Answer:1920

Step-by-step explanation:

Fofino [41]3 years ago

3 0

Answer: 1920

Step-by-step explanation:

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Find the area? need help guys!!

Sergeu [11.5K]

Area = (x+6)(x+2) = x^2 + 8x + 12

8 0

2 years ago

Marie, Shelia, and Martha bought snacks for a girl's sleepover. They each bought the items shown in the following table at the l

creativ13 [48]

Using a system of equations, it is found that the unit prices are:

$2.25 for a bag of chips.

$1.50 for a liter of pop.

$1.75 for a chocolate bar.

For the system:

x is the unit price of a bag of chips.

y is the unit price of liter of pop.

z is the unit price for a chocolate bar.

From the table, the equations are:

$2x + 2y + z = 9.25$

$3x + 4y + z = 14.50$

$x + 3y + 3z = 12$

Replacing the first equation on the second and the third:

$z = 9.25 - 2x - 2y$

$3x + 4y + z = 14.50$

$3x + 4y + 9.25 - 2x - 2y = 14.50$

$x + 2y = 5.25$

$x = 5.25 - 2y$

$x + 3y + 3z = 12$

$x + 3y + 3(9.25 - 2x - 2y) = 12$

$-5x - 3y = -15.75$

$5x + 3y = 15.75$

Since $x = 5.25 - 2y$ :

$5(5.25 - 2y) + 3y = 15.75$

$-7y = -10.5$

$y = \frac{10.5}{7}$

$y = 1.5$

Then:

$x = 5.25 - 2y = 5.25 - 2(1.5) = 2.25$

$z = 9.25 - 2x - 2y = 9.25 - 2(2.25) - 2(1.5) = 1.75$

The unit prices are:

$2.25 for a bag of chips.

$1.50 for a liter of pop.

$1.75 for a chocolate bar.

A similar problem, also solved using a system of equations, is given at brainly.com/question/14183076

4 0

2 years ago

Simplify the expression x³ ÷ x^4×x^5

miss Akunina [59]

Answer is = X^6

Please give me the brainliest

4 0

3 years ago

Find the slope of the line whose equation is 5y = x - 3. a)-3 b)-3/5 c)1/5 d)5

Wewaii [24]

Y=mx+b
m=slope
solve for y

5y=x-3
divide both sides by 5
y=(1/5)x-(3/5)
slope=1/5

C is answer

3 0

3 years ago

Read 2 more answers

In the figure, a square is inside another bigger square.

evablogger [386]

Answer:

Part 1) The length of the diagonal of the outside square is 9.9 units

Part 2) The length of the diagonal of the inside square is 7.1 units

Step-by-step explanation:

step 1

Find the length of the outside square

Let

x -----> the length of the outside square

c ----> the length of the inside square

we know that

$x=a+b=4+3=7\ units$

step 2

Find the length of the inside square

Applying the Pythagoras Theorem

$c^{2}= a^{2}+b^{2}$

substitute

$c^{2}= 4^{2}+3^{2}$

$c^{2}=25$

$c=5\ units$

step 3

Find the length of the diagonal of the outside square

To find the diagonal Apply the Pythagoras Theorem

Let

D -----> the length of the diagonal of the outside square

$D^{2}= x^{2}+x^{2}$

$D^{2}= 7^{2}+7^{2}$

$D^{2}=98$

$D=9.9\ units$

step 4

Find the length of the diagonal of the inside square

To find the diagonal Apply the Pythagoras Theorem

Let

d -----> the length of the diagonal of the inside square

$d^{2}= c^{2}+c^{2}$

$d^{2}= 5^{2}+5^{2}$

$d^{2}=50$

$d=7.1\ units$

7 0

3 years ago

Read 2 more answers