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Tems11 [23]
3 years ago
5

how do you do this 2 problems please help me ITS A PICTURE please help!! Find the area please!!10 points!! Thabk you!!​

Mathematics
2 answers:
Lunna [17]3 years ago
7 0

Answer:22.8

Step-by-step explanation:the 3.4 doesn't need to be added just 5.7 times four because all the sides are equal

Rina8888 [55]3 years ago
5 0

Answer:

for number 4: the area is 19.38 sq cm

for number 6: the area is 57.4 sq mm

Step-by-step explanation:

for number 4:

start with the formula:

A = bh

Then substitute b for 5.7 cm and h for 3.4 cm.

A = 5.7 cm times 3.4 cm

This equals 19.38 sq cm.

for number 6:

start with the formula:

A = 1/2 bh

Substitute b for 14 mm and h for 8.2 mm.

A = 1/2 times 14 mm times 8.2 mm

This equals 57.4 sq mm.

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Alexxx [7]

(?) = (x - 3)(x + 3)

Step-by-step explanation:

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4 0
3 years ago
There are 5 pens in a container on your desk. Among them, 3 will write well but 2 have defective ink cartridges. You will select
Norma-Jean [14]

Answer:

Kindly check explanation

Step-by-step explanation:

Total Number of pens = 5

Number of defective pens = 2

Number of non-defective pens = 3

A.) number of defective pens selected :

X : {0, 1, 2}

It is possible that no defective pen will be selected ; 1 defective will be chosen or both pens are defective.

2.)

Defective as Success (since selecting a defective pen is the point of interest.

3.)

Since selection is done without replacement

Probability of success per selection is different for each selection ;

Number of defective = 2

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P(success on first selection) = 2/5

P(success on second selection) = 1/4

Hence, X is not well approximated by a binomial random variable.

4.) if selection is done with replacement ; then then the probability of success per selection will be the Same for each selection made. Hence, X will be well approximated by a binomial Random variable.

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7 0
3 years ago
I desperately need this question answered. See attached image thanks so much
Dahasolnce [82]

For this case we must follow the steps below:

step 1:

We place each of the given points on a coordinate axis

Step 2:

We join the AC points (represented by the orange line)

We join the BD points (represented by the blue line)

It is observed that the resulting figure after placing the 4 points on a coordinate axis, turns out to be a rhombus.

In addition, the blue and orange lines turn out to be perpendicular, that is, they have an angle of 90 degrees between them. This can be verified by finding the slopes of each of the two straight lines (blue and orange), which must be opposite reciprocal, that is, they comply: m1 * m2 = -1

In this case, the slope of the orange line is m1 = 1 and that of the blue line is m2 = -1

Then m1 * m2 = 1 * -1 = -1, it is verified that they are perpendicular.

Thus, the conclusion is that ABCD is a rhombus and AC is perpendicular to BD.

Answer:

See attached image

Option D

6 0
3 years ago
(a) The Feelgood Gym has a monthly membership fee of $100 and it charges an addi-
Ierofanga [76]

If I use the gym for x hours in a month, the total cost in terms of x will be 1000 + x.

a. Monthly membership fee = $100

Additional amount charged = $1 per hour.

If I use the gym for x hours in a month, the total cost in terms of x will be:

= 1000 + 1(x)

= 1000 + x

b. Also, if the amount charged is $35 per month and $3.50 per hour, the total cost will be:

= 35 + 3.50(x)

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5 0
3 years ago
A cube has a volume of 800 cubic units. the length of the edge of this cube is between which two numbers?
8090 [49]
I set this up as an inequality, 800 \leq  s^{3}.  If you take the cubed root of 800, you get the lower bound of the side length, which is 9.2.  Then I just worked my way up until I hit the first number that put me over a volume of 800.  That number is 9.29, because 9.28 cubed is 799.1 (not high enough) and 9.29 cubed is 801.8.  Therefore, the bounds of the sides exist within a conjunction: 9.2\ \textless \ s\ \textless \ 9.29.  That's the best I could come up with to help on that one.  Wasn't sure if there was another method you were taught at school. I just used common sense more than any rule.
8 0
4 years ago
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