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Scorpion4ik [409]
3 years ago
11

The perimeter of a patio is 16m what is the area

Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0

Answer:

16m

Step-by-step explanation:

The correct answer is 16m for this question.

Formula: L*W

I know this because 4 goes into 16.

Hope this helps.

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What is the area of a circle with a radius of 2.1cm? Use 3.14 for π.
saul85 [17]

Answer: I got's you lol

A≈13.85cm²

And the radius is 2.1

Step-by-step explanation:

Hope this helps let me know :)

3 0
3 years ago
Read 2 more answers
In properties of logarithms, what is log2 25?
spayn [35]
log_a(b)=clog_a(b)=c translates to

a^c=ba^c=b
let's say it equals y

log_2(25)=ylog_2(25)=y
trsnaltes to
2^y=252^y=25
doesn't help us
we can also translate it to
log_2(5^2)log_2(5^2) or 2log_2(5)log_2(5^2)


not sure what you're looking for
8 0
3 years ago
Find the product. 312 × 15 <br><br> A.4,680 <br> B.4,670<br> C. 1,872 <br> D.1,862
lana [24]

Answer:

A. 4,680

Step-by-step explanation:

312*15=4,680

7 0
3 years ago
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Which equation shows a valid step in solving /2x-6+2x+6=0?
AfilCa [17]

An equation which shows a valid step that can be used to solve the given mathematical equation is (\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3

<h3>What is an equation?</h3>

An equation simply refers to a mathematical expression that can be used to show the relationship existing between two (2) or more numerical quantities.

In this exercise, you're required to show a valid step which can be used to solve the given mathematical equation. Since both equations are having a cube root, the first step is to take the cube of both sides.

Take the cube of both sides, we have:

\sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0\\\\(\sqrt[3]{2x - 6})^3 + (\sqrt[3]{2x + 6})^3 = 0^3\\\\(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3

Read more on equations here: brainly.com/question/13170908

#SPJ1

5 0
2 years ago
Solve the linear system using multiplication Elimination.<br><br> 4х + Зу = 8<br> X - 2y = 13
motikmotik
X=5, y=-4
(5,-4)
do you need the work?
5 0
3 years ago
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