Mrs kaushik has a square plote with
1 answer:
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Answer:
Step-by-step explanation:
The standard equation of a hyperbola is given by:
where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²
Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)
The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61
The foci is (h ± c, k) = (±√98, 0). Therefore c = √98
Hence:
c² = a² + b²
(√98)² = (√61)² + b²
98 = 61 + b²
b² = 37
b = √37
Hence the equation of the hyperbola is:
Answer:
a. Check the attached image
b. The Pr(Y > 2) = ½
c. The mean is 2.4
d. The standard deviation is: 2.72
e. The exact value is 1 because it is certain from the given data that any probability will fall within that range.
Step-by-step explanation:
a. An image showing the step by step solution is attached.
b. P(Y > 2) = P(3) + P(4)
= 2/10 + 3/10 = 5/10 = ½
c. The mean is 2.4
d. The standard deviation is: 2.72
e. Check the attached image for the steps.
